以application/json 方式提交然后用在php中读取原始数据流的方式获取在json_encode

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html 如下：

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML>
<HEAD>
<TITLE>后台管理系统登录</TITLE>
<META http-equiv=Content-Type content="text/html; charset=utf-8">
<script src="/docs/js/jquery-1.8.1.min.js" ></script>
</HEAD>
<body>
    name: <input type="text" name="name" id="name" value="tom" /><br />
    age:<input type="text" name="age" id="age" value="22" /><br />
    <textarea name="contents" id="contents"></textarea><br />
    <a href="#" onclick="javascript:tijiao();"> submit </a>

</BODY>
</HTML>
<script>
function tijiao()
{
   $.ajax({
         type: "POST",
         contentType: "application/json",
         url:'/test1.php',// 跳转到 action
         data: '{"name":"'+$('#name').val()+'","age":"'+$('#age').val()+'","contents":"'+$('#contents').val()+'"}',
         dataType: 'json',
         success: function(result) {
           $("#shows").html(result.name + "|"+result.age + "|" + result.contents );
         }
     });
}

</script>

php：

<?php
$string = file_get_contents("php://input");
$res = json_decode($string,true);

echo json_encode($res);