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php数据库查询结果显示 php查询数据库并输出实例
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PHP如何查询数据并显示结果。
这个简单啊！
首页做个前台输入姓名和会员卡信息的页面，我做个简单的页面给你看
!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" ""
html xmlns=""
head
meta http-equiv="Content-Type" content="text/html; charset=utf-8" /
title会员查询系统/title
/head
body
form id="form1" name="form1" method="post" action="test.php"
p
label for="name"/label
input type="text" name="name" id="name" /
/p
p
label for="vipid"/label
input type="text" name="vipid" id="vipid" /
/p
p
input type="submit" name="button" id="button" value="查询" /
/p
/form
/body
/html
然后我给你一个test.php的文件代码：
?php
$name = trim($_POST['name']);
$vipid = trim($_POST['vipid']);
$con = mysql_connect("127.0.0.1","数据库用户名","数据库密码");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
$a = mysql_select_db("数据库名字", $con);
$sql = "select * from kh_customer where name = '$name' and vipid = '$vipid'";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result))
{
echo $row['name'] . " " . $row['data'];
echo "br /";
}
mysql_close($con);
?
页面美化自己去搞！只能帮你这么多了
相关问答
Q1: php查询数据库并在网页上输出结果
$sql = 'SELECT COUNT( * ) FROM DAY WHERE id_u =1' ;
$resault = $db-getAll($sql);
//
function getAll($sql)
{
$res = $this-query($sql);
if ($res !== false)
{
$arr = array();
while ($row = mysql_fetch_assoc($res))
{
$arr[] = $row;
}
return $arr;
}
else
{
return false;
}
}
//
function query($sql, $type = '')
{
if ($this-link_id === NULL)
{
$this-connect($this-settings['dbhost'], $this-settings['dbuser'], $this-settings['dbpw'], $this-settings['dbname'], $this-settings['charset'], $this-settings['pconnect']);
$this-settings = array();
}
if ($this-queryCount++ = 99)
{
$this-queryLog[] = $sql;
}
if ($this-queryTime == '')
{
if (PHP_VERSION = '5.0.0')
{
$this-queryTime = microtime(true);
}
else
{
$this-queryTime = microtime();
}
}
/* 当当前的时间大于类初始化时间的时候，自动执行 ping 这个自动重新连接操作 */
if (PHP_VERSION = '4.3' time() $this-starttime + 1)
{
mysql_ping($this-link_id);
}
if (!($query = mysql_query($sql, $this-link_id)) $type != 'SILENT')
{
$this-error_message[]['message'] = 'MySQL Query Error';
$this-error_message[]['sql'] = $sql;
$this-error_message[]['error'] = mysql_error($this-link_id);
$this-error_message[]['errno'] = mysql_errno($this-link_id);
$this-ErrorMsg();
return false;
}
if (defined('DEBUG_MODE') (DEBUG_MODE 8) == 8)
{
$logfilename = $this-root_path . DATA_DIR . '/mysql_query_' . $this-dbhash . '_' . date('Y_m_d') . '.log';
$str = $sql . "\n\n";
if (PHP_VERSION = '5.0')
{
file_put_contents($logfilename, $str, FILE_APPEND);
}
else
{
$fp = @fopen($logfilename, 'ab+');
if ($fp)
{
fwrite($fp, $str);
fclose($fp);
}
}
}
return $query;
}
Q2: php如何查询数据库表中的数据并显示
这个简单啊！
首页做个前台输入姓名和会员卡信息的页面，我做个简单的页面给你看
!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "
html xmlns="
head
meta http-equiv="Content-Type" content="text/html; charset=utf-8" /
title会员查询系统/title
/head
body
form id="form1" name="form1" method="post" action="test.php"
p
label for="name"/label
input type="text" name="name" id="name" /
/p
p
label for="vipid"/label
input type="text" name="vipid" id="vipid" /
/p
p
input type="submit" name="button" id="button" value="查询" /
/p
/form
/body
/html
然后我给你一个test.php的文件代码：
?php
$name = trim($_POST['name']);
$vipid = trim($_POST['vipid']);
$con = mysql_connect("127.0.0.1","数据库用户名","数据库密码");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
$a = mysql_select_db("数据库名字", $con);
$sql = "select * from kh_customer where name = '$name' and vipid = '$vipid'";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result))
{
echo $row['name'] . " " . $row['data'];
echo "br /";
}
mysql_close($con);
?
页面美化自己去搞！只能帮你这么多了
Q3: 怎样用php查询数据库里的一个数据并显示
面向过程:
$sql = "select t_bumen from t_xinxi where id=111"; //Sql语句
$result = mysql_fetch_assoc(mysql_query($sql)); //执行sql语句并以关联数组保存
print_r($result); //输出数组
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