php判断json数据 PHP判断JSON数据是否存在key

php怎么判断一个字符串是不是json

function is_not_json($str){  

    return is_null(json_decode($str));

}

function is_json($string) { 

 json_decode($string);

 return (json_last_error() == JSON_ERROR_NONE);

}

相关问答

Q1: php 循环判断，判断json里面的数据，大神们帮帮忙啊

$str = '{"queryString":"select id , name from user LIMIT 0, 30 ","data":[{"0":"1","id":"1","1":"aa","name":"aa"},{"0":"2","id":"2","1":"\u5c0f\u4f19\u4f34","name":"\u5c0f\u4f19\u4f34"},{"0":"3","id":"3","1":"\u5c0f\u4f19\u4f34","name":"\u5c0f\u4f19\u4f34"},{"0":"4","id":"4","1":"44","name":"44"},{"0":"5","id":"5","1":"","name":""},{"0":"6","id":"6","1":"","name":""},{"0":"7","id":"7","1":"","name":""},{"0":"8","id":"8","1":"","name":""},{"0":"9","id":"9","1":"","name":""},{"0":"10","id":"10","1":"jiejie","name":"jiejie"},{"0":"11","id":"11","1":"jiejie","name":"jiejie"}]}';

foreach (json_decode($str) as $v)

{

if(is_array($v))

{

foreach($v as $value)

{

echo "当前的name 为: {$value-name} id : {$value-id}";

}

}

}

中文不管 你取得是对应的name值

Q2: PHP怎么判断是否是JSON数据

你可以把JSON字符串转成数组，数组转过来不是数组那肯定不是JSON数据。

Q3: php 判断是不是json格式

if(!json_decode($json))

{

//不是

}

else

{

//是

}

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