php数据组合 php数组相加组合数据

php 数组组合问题

$array_old = array(

       array(

          'name' = 'param1',

           'isNull' = 1,

           'type' = 'int',

           'value' = 1,

       ),

       array(

           'name' = 'param2',

           'isNull' = 0,

           'type' = 'string',

           'value' = 'test',

       ),

);

相关问答

Q1: php中的两组数如何相间组合到一起

1.你先选择你想要组合的图形 2.右击选择弹出的“组合图形” 3.保存文件。

Q2: php 如何计算数组中数字的组合？

$arr = array(1,2,2,3,3,3,4,5,3,2,3,3);$num = count(array_count_values($arr));// 或者$num = count(array_unique($arr));

Q3: PHP问题： PHP二维数据组合

1:

[id] = 408

[type] = china

[reality] = 120.00

[days] = 2016-06-20

2:

[id] = 408

[totalsave] = 200.00

[days] = 2016-06-20

3:

[id] = 408

[totalsave] = 3800.00

[days] = 2016-06-20

4:

[id] = 408

[totalwithdraw] = 92.00

[should] = 0.7176

[days] = 2016-06-20

5:

[id] = 408

[totalwithdraw] = 3908.00

[should] = 14.8504

[days] = 2016-06-20

结论

[id] = 408

[totalwithdraw] = 82.00

[should] = 0.6396

[days] = 2016-06-20

[totalsave] = 3800.00

[type] = 中文

[reality] = 0.00

看不出有神马逻辑关系。。

Q4: PHP 多个数组的排列组合

$a = array(1,2,3,4,5,6,7);

$b = array(1,2,3);

$c = array(1,2,3,4,5,6,7,8,9,10);

$d = array($a,$b,$c);

//计算每一个数组的长度

$len = 1;

$arrLen = count($d); //需要排列数组有多少个

$recIndex = null; //记录当前该取的位置

//foreach 计数

$count_3 = 0;

foreach ($d as $key = $value) {

$lenRec[$count_3] = count($value);

$len = $lenRec[$count_3]*$len;

$recIndex[] = 0;//第一次全部取第0个

$count_3++;

}

//算出% 的值

$count = 1;

foreach ($lenRec as $key = $value) {

$moduloVal = 1;

if($arrLen == $count){

$modulo[] = count($d[$arrLen-1]); //等于最后一个的长度

}else{

$count_1 = 1;

foreach ($lenRec as $index = $item) {

$count_1 $count $moduloVal = $moduloVal*$item;

$count_1 ++;

}

$modulo[] = $moduloVal;

}

$count ++;//为了防止$d key是有值的 不是自然序列 需要计数

}

$i = 1;

while ( $i = $len) {

$html = '';

$count_2 = 0;// 取模

$temp = '';

foreach ($d as $value) {

$html .= $value[$recIndex[$count_2]%$lenRec[$count_2]].",";

$count_2 ++;

}

echo $html."br";

foreach ($modulo as $key = $value) {

if($i%$value == 0 $key $arrLen - 1 ){

$recIndex[$key] = $recIndex[$key] +1;

}

if($key == $arrLen - 1){

if($i%$value == 0){

$recIndex[$key] = 0;

}else{

$recIndex[$key] = $recIndex[$key] +1;

}

}

}

$i ++;

//改变获取的位置

}

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