dom4j 读取xml

package core.util;import java.io.File;import java.util.Iterator;import java.util.List;import org.dom4j.Attribute;import org.dom4j.Document;import org.dom4j.DocumentException;import org.dom4j.Element;import org.dom4j.io.SAXReader;public class Reader {public static String findUrl(String xmlPath,String actionName,String htmlUrlName){String remoteUrl = "";SAXReader reader = new SAXReader();try {//读取xmlDocument document = reader.read(new File(xmlPath));//获取xml根路径Element package_root=document.getRootElement();//获root下的所有action子节点List<Element> actions = package_root.elements("action");for (Element action: actions) {//获取action中 属性为name的值 <action name="login"></action> 这里获取的就是loginif(action.attribute("name").getValue().equals(actionName)){//获取name的值等于xx的action下面的子节点List<Element> urls = action.elements("remoteHtmlUrl");for (Element url: urls) {if(url.attribute("name").getValue().equals(htmlUrlName)){//获取该子节点下面的值<url>http://www.baidu.com</url> 这里获取的是http://www.baidu.comremoteUrl = url.getText();return remoteUrl;}}}}} catch (DocumentException e) {System.out.println("xml路径不正确，请确认后重试");e.printStackTrace();}return remoteUrl;}}

<?xml version="1.0" encoding="UTF-8"?><package> <action name="login" class="loginController"> <remoteHtmlUrl name="register">http://www.baidu.com</remoteHtmlUrl> <remoteHtmlUrl name="login">http://www.google.com</remoteHtmlUrl> </action></package>