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vb.net由点画曲线 vb如何画折线图
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vb.net 画二维数组的曲线图
Private Sub PictureBox2_Paint(sender As Object, e As PaintEventArgs) Handles PictureBox2.Paint
Dim points As New List(Of Point)
points.Add(New Point(0, 0))
points.Add(New Point(1, 10))
points.Add(New Point(3, 15))
points.Add(New Point(14, 0))
points.Add(New Point(20, 60))
points.Add(New Point(40, 20))
points.Add(New Point(70, 50))
e.Graphics.DrawCurve(Pens.Red, points.ToArray)
End Sub
供参考vb.net由点画曲线,points可设为全局变量vb.net由点画曲线,那样add随便在哪增加vb.net由点画曲线,想要看见看上去动态的图,那就在新增完n个后,继续增加n+1个之时,放弃points中的第一个。
相关问答
Q1: vb.net 绘制实时温度曲线
这个要用GDI+画。要看vb.net由点画曲线你.net版本。
以下是VS2005中vb.net由点画曲线的一段代码。
Me.PictureBox1.Height = 450
Me.PictureBox1.Width = 880
Dim gr As Graphics '定义画布
Dim bp As New Bitmap(880, 450) '定义位图,并进行赋值
Dim p As New Pen(Color.Black) '定义画笔
p.Width = 2 '宽度2
p.DashStyle = Drawing2D.DashStyle.Solid '样式直线
PictureBox1.Image = bp
gr = Graphics.FromImage(PictureBox1.Image)
gr.FillRectangle(Brushes.White, New Rectangle(0, 0, PictureBox1.Width, PictureBox1.Height))
gr.DrawLine(p, a, b, a, .Height - b) '绘制纵坐标
gr.DrawLine(p, a, .Height - b, .Width - a, .Height - b) '绘制横坐标
Q2: 在VB中如何通过已知的几个点绘制样条曲线
Function hypot(ByVal X As Single, ByVal Y As Single)
hypot = Sqr(X ^ 2 + Y ^ 2)
End Function
Sub tspLine(ByVal n As Integer, ByVal ch As Integer, ByVal tx1 As Single, ByVal tx2 As Single, ByVal ty1 As Single, ByVal ty2 As Single)
Dim a(1000) As Single, b(1000) As Single, c(1000) As Single, dX(1000) As Single, dY(1000) As Single
Dim qx(1000) As Single, qy(1000) As Single
Dim tt As Single, bx3 As Single, bx4 As Single, by3 As Single, by4 As Single
Dim cx As Single, cy As Single, t(1000) As Single, px(1000) As Single, py(1000) As Single
Dim u(3000) As Single, v(3000) As Single, i As Integer
num = 0
For i = 1 To n
t(i) = hypot(X(i) - X(i - 1), Y(i) - Y(i - 1))
Next i
Select Case ch
Case 0 '抛物条件
u(0) = (X(1) - X(0)) / t(1): u(1) = (X(2) - X(1)) / t(2)
u(2) = (u(1) - u(0)) / (t(2) + t(1))
tx1 = u(0) - u(2) * t(1)
u(0) = (Y(1) - Y(0)) / t(1): u(1) = (Y(2) - Y(1)) / t(2)
u(2) = (u(1) - u(0)) / (t(2) + t(1))
ty1 = u(0) - u(2) * t(1)
u(0) = (X(n) - X(n - 1)) / t(n): u(1) = (X(n - 1) - X(n - 2)) / t(n - 1)
u(2) = (u(0) - u(1)) / (t(n) + t(n - 1))
tx2 = u(0) + u(2) * t(n)
u(0) = (Y(n) - Y(n - 1)) / t(n): u(1) = (Y(n - 1) - Y(n - 2)) / t(n - 1)
u(2) = (u(0) - u(1)) / (t(n) + t(n - 1))
ty2 = u(0) + u(2) * t(n)
Case 1 '夹持条件
a(0) = 1: c(0) = 0: dX(0) = tx1: dY(0) = ty1
a(n) = 1: b(n) = 0: dX(n) = tx2: dY(n) = ty2
Case 2 '自由条件
a(0) = 2: c(0) = 1
dX(0) = 3 * (X(1) - X(0)) / t(1): dY(0) = 3 * (Y(1) - Y(0)) / t(1)
a(n) = 2: b(n) = 1
dX(n) = 3 * (X(n) - X(n - 1)) / t(n): dY(n) = 3 * (Y(n) - Y(n - 1)) / t(n)
Case 3 '循环条件
a(0) = 2: c(0) = 1
dX(0) = 3 * (X(1) - X(0)) / t(1) - (t(1) * (X(2) - X(1)) / t(2) - X(1) + X(0)) / (t(1) + t(2))
dY(0) = 3 * (Y(1) - Y(0)) / t(1) - (t(1) * (Y(2) - Y(1)) / t(2) - Y(1) + Y(0)) / (t(1) + t(2))
a(n) = 2: b(n) = 1
dX(n) = 3 * (X(n) - X(n - 1)) / t(n)
dX(n) = dX(n) + (X(n) - X(n - 1) - t(n) * (X(n - 1) - X(n - 2)) / t(n - 1)) / (t(n) + t(n - 1))
dY(n) = 3 * (Y(n) - Y(n - 1)) / t(n)
dY(n) = dY(n) + (Y(n) - Y(n - 1) - t(n) * (Y(n - 1) - Y(n - 2)) / t(n - 1)) / (t(n) + t(n - 1))
End Select
'计算方程组系数阵和常数阵
For i = 1 To n - 1
a(i) = 2 * (t(i) + t(i + 1)): b(i) = t(i + 1): c(i) = t(i)
dX(i) = 3 * (t(i) * (X(i + 1) - X(i)) / t(i + 1) + t(i + 1) * (X(i) - X(i - 1)) / t(i))
dY(i) = 3 * (t(i) * (Y(i + 1) - Y(i)) / t(i + 1) + t(i + 1) * (Y(i) - Y(i - 1)) / t(i))
Next i
'采用追赶法解方程组
c(0) = c(0) / a(0)
For i = 1 To n - 1
a(i) = a(i) - b(i) * c(i - 1): c(i) = c(i) / a(i)
Next i
a(n) = a(n) - b(n) * c(i - 1)
qx(0) = dX(0) / a(0): qy(0) = dY(0) / a(0)
For i = 1 To n
qx(i) = (dX(i) - b(i) * qx(i - 1)) / a(i)
qy(i) = (dY(i) - b(i) * qy(i - 1)) / a(i)
Next i
px(n) = qx(n): py(n) = qy(n)
For i = n - 1 To 0 Step -1
px(i) = qx(i) - c(i) * px(i + 1)
py(i) = qy(i) - c(i) * py(i + 1)
Next i
'计算曲线上点vb.net由点画曲线的坐标
For i = 0 To n - 1
bx3 = (3 * (X(i + 1) - X(i)) / t(i + 1) - 2 * px(i) - px(i + 1)) / t(i + 1)
bx4 = ((2 * (X(i) - X(i + 1)) / t(i + 1) + px(i) + px(i + 1)) / t(i + 1)) / t(i + 1)
by3 = (3 * (Y(i + 1) - Y(i)) / t(i + 1) - 2 * py(i) - py(i + 1)) / t(i + 1)
by4 = ((2 * (Y(i) - Y(i + 1)) / t(i + 1) + py(i) + py(i + 1)) / t(i + 1)) / t(i + 1)
tt = 0
While (tt = t(i + 1))
cx = X(i) + (px(i) + (bx3 + bx4 * tt) * tt) * tt
cy = Y(i) + (py(i) + (by3 + by4 * tt) * tt) * tt
u1(num) = cx: v1(num) = cy: num = num + 1: tt = tt + 0.5
Wend
u1(num) = X(i + 1): v1(num) = Y(i + 1): num = num + 1
Next i
End Sub
Private Sub Command1_Click()
Dim i As Long
'Picture1.Scale (0, 0)-(640, 550)
DrawWidth = 3
Picture1.Cls
'If Check1.Value Then Command2_Click
'X(0) = 1
'Y(0) = 1
'X(t - 1) = 638
'Y(t - 1) = 548
Picture1.ForeColor = QBColor(10)
For i = 0 To t - 1
Picture1.Line (X(i) - 1, Y(i) - 1)-(X(i) + 1, Y(i) + 1), QBColor(10), B
Picture1.Print i
Next i
Picture1.ForeColor = QBColor(12)
DrawWidth = 1
tspLine t - 1, 2, 0, 0, 0, 0
Picture1.PSet (u1(0), v1(0))
For i = 1 To num - 1
Picture1.Line -(u1(i), v1(i))
'For de = 1 To 12000: Next de 'Sleep 1
Next i
Picture1.ForeColor = QBColor(10)
For i = 0 To t - 1
Picture1.Line (X(i) - 1, Y(i) - 1)-(X(i) + 1, Y(i) + 1), QBColor(10), B
Picture1.Print i
Next i
End Sub
Q3: vb.net绘制曲线图
。net 其实还是很好绘制图形vb.net由点画曲线的
vb.net由点画曲线你可以看下 Graphics 类
Dim d As New Bitmap(Me.Width, Me.Height) ‘一个图片吧
Dim g As Graphics = Graphics.FromImage(d)’绘制 准备在这个图片是进行
然后 就是你绘制的东西vb.net由点画曲线了
线 就是 g.DrawLine()
圆 弧度 就用 g.DrawArc(Pens.Black, New Rectangle(0, 0, 400, 200), 0, 360)
复杂的就是 g.DrawBezier()
等 如果你用的是 VS的 编译 上面都有详细的参数说明
Dim d As New Bitmap(Me.Width, Me.Height)
Dim g As Graphics = Graphics.FromImage(d)
g.DrawArc(Pens.Black, New Rectangle(0, 0, 200, 200), 0, 360)
g.DrawLine(Pens.Red, New Point(0, 0), New Point(200, 200))
g.DrawLines(Pens.Green, New Point() {New Point(0, 0), New Point(50, 40), New Point(50, 80), New Point(90, 70), New Point(100, 400)})
g.DrawBezier(Pens.Yellow, New Point(0, 100), New Point(0, 0), New Point(200, 0)vb.net由点画曲线, New Point(200, 200))
g.Dispose()
Me.BackgroundImage = d
Q4: vb如何把已知点绘制成曲线
这是画点vb.net由点画曲线的vb.net由点画曲线:
Private Sub Form_Click()
Dim X(7) As Integer, Y(7) As Integer, i%
Form1.Scale (-15, 15)-(15, -15)
Form1.Line (0, 0)-(15, 0)
Form1.Line (0, 15)-(0, 0)
For i = 0 To 12 'Step 1.2 'X轴坐标
Form1.Line (i, 0.1)-(i, 0)
CurrentX = i
CurrentY = -1
Form1.Print i
Next i
For i = 0 To 12 'Step 1.2 'Y轴坐标
Form1.Line (0, i)-(0.3, i)
CurrentX = -0.5
CurrentY = i
Form1.Print i
Next i
X(0) = 0: X(1) = 2: X(2) = 4: X(3) = 6: X(4) = 8: X(5) = 10: X(6) = 12: X(7) = 14
Y(0) = 0: Y(1) = 1: Y(2) = 3: Y(3) = 4: Y(4) = 3: Y(5) = 2: Y(6) = 1: Y(7) = 0
For i = 0 To 7
Form1.PSet (X(i), Y(i)), vbRed
Next i
End Sub
Q5: 想在VB中根据数据库的数据画曲线变化图,如何画?用什么方法
VB提供的绘制图形的方法:(可以在窗体上或PicTureBox控件上使用)
与你主题相关的有:
1,绘制直线
object.Line (x1,y1) - (x2,y2), [color]
其中:(x1,y1) 和 (x2,y2)分别是平面上的两个点坐标。
2,绘制一点:
object.PSet (x,y), [color]
其中:(x1,y1) 是平面上的一个点坐标。
3,绘制图形的笔尖的粗细:
object.DrawWidth = size
默认粗细为1。
4,绘制图形的线条的颜色设置:
1)Object.ForeColor = QbColor(n) :n = 0 -- 15
2) 或者在使用上述方法时,在后边跟的参数[color]
思路:
绘制曲线,就是根据函数关系:y = f(x),采用描点法,在某一区域范围内,根据x计算y,然后用
PSet (x,y)实现曲线的绘制。
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