vb.net2维数组 vb二维数组元素个数

VB.NET 二维数组 引用其中的一维

OPCItemIDsData(j,其中一维）即可。

如果前面方法有规定，不能用二维数组的格式，那么你可以自己定义一个一维数组，将二维数组的某一维度的全部数值赋值给这个数组，在引用这个数组：

dim OPCItemIDsDataBuf(x) as ...

for i = 1 to x

OPCItemIDsDataBuf(j）=OPCItemIDsData(j,其中一维）

next i

其中x是数组的最大下标

相关问答

Q1: VB.NET 二维数组问题

根据你的语句，上下标是确定的，所以定义语句修改为：

Dim ary(UBound(temp), 1) As String '声明二维数组

Q2: VB.net中，请问如何将二维数组的数值显示在listview控件中？

将二位数组转成DataTable，网上找的不知道成不成

public static DataTable ConvertToDataTable(string[,] arr)

{

DataTable dataSouce = new DataTable();

for (int i = 0; i arr.GetLength(1); i++)

{

DataColumn newColumn = new DataColumn(i.ToString(), arr[0, 0].GetType());

dataSouce.Columns.Add(newColumn);

}

for (int i = 0; i arr.GetLength(0); i++)

{

DataRow newRow = dataSouce.NewRow();

for (int j = 0; j arr.GetLength(1); j++)

{

newRow[j.ToString()] = arr[i, j];

}

dataSouce.Rows.Add(newRow);

}

return dataSouce;

}

Q3: VB.NET 2维数组排序排序和赋值问题

窗体上添加3个标签，1个按钮，在按钮的单击事件里写代码，如下：

Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click

Dim a(,) As Integer = {{5, 6}, {1, 3}, {8, 9}, {72, 1}, {63, 4}}

Dim Temp As Integer

Dim i As Integer

Dim j As Integer

Dim x As Integer

Dim y As Integer

'显示排序前的数据

Label1.Text = "排序前数据：" vbCrLf

For i = 0 To 4

Label1.Text = Label1.Text a(i, 0) " " a(i, 1) vbCrLf

Next

For i = 0 To 3

For j = i + 1 To 4

If a(i, 0) a(j, 0) Then

Temp = a(i, 0)

a(i, 0) = a(j, 0)

a(j, 0) = Temp

Temp = a(i, 1)

a(i, 1) = a(j, 1)

a(j, 1) = Temp

End If

Next

Next

'显示排序前的数据

Label2.Text = "排序后数据：" vbCrLf

For i = 0 To 4

Label2.Text = Label2.Text a(i, 0) " " a(i, 1) vbCrLf

Next

'把第3行元素赋予X,Y

x = a(2, 0)

y = a(2, 1)

'输出X,Y

Label3.Text = "X=" x vbCrLf "Y=" y

End Sub

Q4: VB.net中如何求出2维数组，每个维度上的值得个数

每行的数字个数不同,你说的这是不规则数组,解决方案如下:

Dim b As String = ""

Dim a As Integer()() = New Integer(9)() {}

a(0) = New Integer() {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}

a(1) = New Integer() {0, 3, 4, 5}

a(2) = New Integer() {0, 4, 5, 6, 7}

a(3) = New Integer() {0, 6, 5, 8, 9, 1}

a(4) = New Integer() {0, 2, 5, 1, 7}

a(5) = New Integer() {0, 4, 2, 6, 7, 3}

a(6) = New Integer() {0, 4, 5, 3, 2}

a(7) = New Integer() {0, 4, 1, 6, 2, 8, 5, 3}

a(8) = New Integer() {0, 4, 9, 6, 3, 5, 7}

a(9) = New Integer() {0, 1, 5, 9, 7, 6, 2, 4, 3, 8}

For i As Integer = 0 To a.GetUpperBound(0)

b = "第" i + 1 "行有" a(i).GetUpperBound(0) + 1 "个数" vbCrLf

Next

MessageBox.Show(b)