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Java多元多次方程代码 多元多次方程的次数
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JAVA程序实现求解二元多次方程组
public class Main {
public static void main(String[] args) {
for(int x=0;x=0;x++)
{
for(int y =0;y=0;y++)
{
if((x*x+2*x*y+x==42)(y*y+2*x*y+x==42))
{
System.out.println(x+" "+y);
}
}
}
}
}
里面方程组随便设置，有些可能无解 就没答案
相关问答
Q1: JAVA编写求解一元多次方程的程序，要求如下：
import java.io.*;
import java.util.*;public class SolveEquation
{
void print()throws IOException
{
char ch='y';
System.out.println("求解几次方程？1：一次 2：二次 3：三次");
Scanner sLine=new Scanner(System.in);
int pm=sLine.nextInt();
if(pm==1)
{
System.out.println("你选择的是一元一次方程:");
SolveEquation.SolveSimpleEquation fc=new SolveEquation().new SolveSimpleEquation();
fc.SolveSimpleEquation();
}
else if(pm==2)
{
System.out.println("你选择的是一元二次方程:");
SolveEquation.SolveQuadraticEquation fc=new SolveEquation().new SolveQuadraticEquation();
fc.SolveQuadraticEquation();
}
else if(pm==3)
{
System.out.println("你选择的是一元三次方程:");
SolveEquation.SolveCubicEquation fc=new SolveEquation().new SolveCubicEquation();
fc.SolveCubicEquation();
}
else
{
print();
}
System.out.println("你是否想继续:(y/n)");
ch=(char)System.in.read()()
System.in.skip(2);
if(ch=='y')
{
print();
}
else if(ch=='n')
{
System.out.println("Good luck!");
}
else
{
print();
}
public static void main (String args[]) throws IOException
{
SolveEquation se=new SolveEquation();
se.print();
}
interface I1
{
void SolveCubicEquation();
}
interface I2
{
void SolveQuadraticEquation();
}
interface I3
{
void SolveSimpleEquation();
}
class SolveCubicEquation implements I1
{
public void SolveCubicEquation()
{
System.out.println("请输入形如一元三次方程mx^3+nx^2+tx+s=0的四个系数");
Scanner sce=new Scanner(System.in);
double m=sce.nextDouble();
double n=sce.nextDouble();
double t=sce.nextDouble();
double s=sce.nextDouble();
if(m==0)
{
System.out.print("输入错误!");
}
else
{
double a=n/m;
double b=t/m;
double c=s/m;
double q=(a*a-3*b)/9;
double r=(2*a*a*a-9*a*b+27*c)/54;
if(r*rq*q*q)
{
System.out.println("此方程有三个解:");
t=Math.acos(r/Math.sqrt(q*q*q));
double x1=-2*Math.sqrt(q)*Math.cos(t/3)-a/3;
double x2=-2*Math.sqrt(q)*Math.cos((t+2*Math.PI)/3)-a/3;
double x3=-2*Math.sqrt(q)*Math.cos((t-2*Math.PI)/3)-a/3;
System.out.println("x1="+x1+","+"x2="+x2+","+"x3="+x3);
}
else
{
System.out.println("此方程只有一个解:");
int sgn=(r=0)?1:-1;
double u=-sgn*Math.pow((Math.abs(r)+Math.sqrt(r*r-q*q*q)),1./3);
double v=(u!=0)?q/u:0;
double x1=u+v-a/3;
System.out.println("x="+x1);
}
}
}
}
class SolveQuadraticEquation implements I2
{
public void SolveQuadraticEquation()
{
System.out.println("请输入形如一元二次方程ax^2+bx+c=0的三个系数");
Scanner sce=new Scanner(System.in);
double a=sce.nextDouble();
double b=sce.nextDouble();
double c=sce.nextDouble();
if(a==0)
{
System.out.print("输入错误!");
}
else
{
double d=b*b-4*a*c;
if(d0)
{
double x1=(-b+Math.sqrt(d))/2*a;
double x2=(-b+Math.sqrt(d))/2*a; System.out.println("有两个实根x1="+x1+","+"x2="+x2);
}
else if(d==0)
{
System.out.println("有一个实根"+(-b/2*a));
}
else if(d0)
{
double Re=-b/(2*a);
double Im=Math.sqrt(-d)/(2*a);
System.out.println("实部="+Re+" "+"虚部="+Im);
}
}
}
}
class SolveSimpleEquation implements I3
{
public void SolveSimpleEquation()
{
System.out.println("请输入形如一元一次方程ax+b=0的两个系数");
Scanner sce=new Scanner(System.in);
double a=sce.nextDouble();
double b=sce.nextDouble();
if(a==0)
{
System.out.print("输入错误!");
}
else
{
System.out.println("方程的根是x="+(-b/a));
}
}
}
}
Q2: 谁帮我写一个多元一次方程自动求解的程序啊 用JAVA写
可以考虑线性代数多元一次方程解决方案
比如：
3x + 2y + 5z = 22
2x - 3y + 7z = 17
x + 6y - 3z = 4
则转化系数为行列式数组
int[][] param = {
{3, 2, 5, 22},
{2, -3, 7, 17},
{1, 6, -3, 4}
};
参考编码：
public static void main(String[] args) throws Exception {
int[][] param = {
{3, 2, 5, 22},
{2, -3, 7, 17},
{1, 6, -3, 4}
};
double[] result = new double[param.length];
double a = calc(param);
for (int i = 0; i param.length; i++) {
int[][] param2 = new int[param.length][param.length];
for (int m = 0; m param2.length; m++) {
for (int n = 0; n param2[m].length; n++) {
if (n == i) {
param2[m][n] = param[m][param[m].length - 1];
} else {
param2[m][n] = param[m][n];
}
}
}
result[i] = calc(param2) / a;
}
System.out.print("[");
for (int i = 0; i result.length; i++) {
if (i != 0) System.out.print(", ");
System.out.print(result[i]);
}
System.out.println("]");
}
private static int calc(int[][] param) {
int sum = 0;
int length = param.length;
for (int i = 0; i length; i++) {
int x = i;
int tmp = 1, tmp2 = 1;
for (int m = 0; m length; m++) {
tmp *= param[(x + m) % length][m];
tmp2 *= param[(x + m) % length][Math.abs(length - 1 - m) % length];
}
sum += tmp;
sum -= tmp2;
}
return sum;
}
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