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java家谱代码 java家族的姓氏
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JAVA代码
连连看java源代码
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
public class lianliankan implements ActionListener
{
JFrame mainFrame; //主面板
Container thisContainer;
JPanel centerPanel,southPanel,northPanel; //子面板
JButton diamondsButton[][] = new JButton[6][5];//游戏按钮数组
JButton exitButton,resetButton,newlyButton; //退出，重列，重新开始按钮
JLabel fractionLable=new JLabel("0"); //分数标签
JButton firstButton,secondButton; //分别记录两次被选中的按钮
int grid[][] = new int[8][7];//储存游戏按钮位置
static boolean pressInformation=false; //判断是否有按钮被选中
int x0=0,y0=0,x=0,y=0,fristMsg=0,secondMsg=0,validateLV; //游戏按钮的位置坐标
int i,j,k,n;//消除方法控制
public void init(){
mainFrame=new JFrame("JKJ连连看");
thisContainer = mainFrame.getContentPane();
thisContainer.setLayout(new BorderLayout());
centerPanel=new JPanel();
southPanel=new JPanel();
northPanel=new JPanel();
thisContainer.add(centerPanel,"Center");
thisContainer.add(southPanel,"South");
thisContainer.add(northPanel,"North");
centerPanel.setLayout(new GridLayout(6,5));
for(int cols = 0;cols 6;cols++){
for(int rows = 0;rows 5;rows++ ){
diamondsButton[cols][rows]=new JButton(String.valueOf(grid[cols+1][rows+1]));
diamondsButton[cols][rows].addActionListener(this);
centerPanel.add(diamondsButton[cols][rows]);
}
}
exitButton=new JButton("退出");
exitButton.addActionListener(this);
resetButton=new JButton("重列");
resetButton.addActionListener(this);
newlyButton=new JButton("再来一局");
newlyButton.addActionListener(this);
southPanel.add(exitButton);
southPanel.add(resetButton);
southPanel.add(newlyButton);
fractionLable.setText(String.valueOf(Integer.parseInt(fractionLable.getText())));
northPanel.add(fractionLable);
mainFrame.setBounds(280,100,500,450);
mainFrame.setVisible(true);
}
public void randomBuild() {
int randoms,cols,rows;
for(int twins=1;twins=15;twins++) {
randoms=(int)(Math.random()*25+1);
for(int alike=1;alike=2;alike++) {
cols=(int)(Math.random()*6+1);
rows=(int)(Math.random()*5+1);
while(grid[cols][rows]!=0) {
cols=(int)(Math.random()*6+1);
rows=(int)(Math.random()*5+1);
}
this.grid[cols][rows]=randoms;
}
}
}
public void fraction(){
fractionLable.setText(String.valueOf(Integer.parseInt(fractionLable.getText())+100));
}
public void reload() {
int save[] = new int[30];
int n=0,cols,rows;
int grid[][]= new int[8][7];
for(int i=0;i=6;i++) {
for(int j=0;j=5;j++) {
if(this.grid[i][j]!=0) {
save[n]=this.grid[i][j];
n++;
}
}
}
n=n-1;
this.grid=grid;
while(n=0) {
cols=(int)(Math.random()*6+1);
rows=(int)(Math.random()*5+1);
while(grid[cols][rows]!=0) {
cols=(int)(Math.random()*6+1);
rows=(int)(Math.random()*5+1);
}
this.grid[cols][rows]=save[n];
n--;
}
mainFrame.setVisible(false);
pressInformation=false; //这里一定要将按钮点击信息归为初始
init();
for(int i = 0;i 6;i++){
for(int j = 0;j 5;j++ ){
if(grid[i+1][j+1]==0)
diamondsButton[i][j].setVisible(false);
}
}
}
public void estimateEven(int placeX,int placeY,JButton bz) {
if(pressInformation==false) {
x=placeX;
y=placeY;
secondMsg=grid[x][y];
secondButton=bz;
pressInformation=true;
}
else {
x0=x;
y0=y;
fristMsg=secondMsg;
firstButton=secondButton;
x=placeX;
y=placeY;
secondMsg=grid[x][y];
secondButton=bz;
if(fristMsg==secondMsg secondButton!=firstButton){
xiao();
}
}
}
public void xiao() { //相同的情况下能不能消去。仔细分析，不一条条注释
if((x0==x (y0==y+1||y0==y-1)) || ((x0==x+1||x0==x-1)(y0==y))){ //判断是否相邻
remove();
}
else{
for (j=0;j7;j++ ) {
if (grid[x0][j]==0){ //判断第一个按钮同行哪个按钮为空
if (yj) { //如果第二个按钮的Y坐标大于空按钮的Y坐标说明第一按钮在第二按钮左边
for (i=y-1;i=j;i-- ){ //判断第二按钮左侧直到第一按钮中间有没有按钮
if (grid[x][i]!=0) {
k=0;
break;
}
else //K=1说明通过了第一次验证
}
if (k==1) {
linePassOne();
}
}
if (yj){ //如果第二个按钮的Y坐标小于空按钮的Y坐标说明第一按钮在第二按钮右边
for (i=y+1;i=j ;i++ ){ //判断第二按钮左侧直到第一按钮中间有没有按钮
if (grid[x][i]!=0){
k=0;
break;
}
else
}
if (k==1){
linePassOne();
}
}
if (y==j ) {
linePassOne();
}
}
if (k==2) {
if (x0==x) {
remove();
}
if (x0x) {
for (n=x0;n=x-1;n++ ) {
if (grid[n][j]!=0) {
k=0;
break;
}
if(grid[n][j]==0 n==x-1) {
remove();
}
}
}
if (x0x) {
for (n=x0;n=x+1 ;n-- ) {
if (grid[n][j]!=0) {
k=0;
break;
}
if(grid[n][j]==0 n==x+1) {
remove();
}
}
}
}
}
for (i=0;i8;i++ ) { //列
if (grid[i][y0]==0) {
if (xi) {
for (j=x-1;j=i ;j-- ) {
if (grid[j][y]!=0) {
k=0;
break;
}
else
}
if (k==1) {
rowPassOne();
}
}
if (xi) {
for (j=x+1;j=i;j++ ) {
if (grid[j][y]!=0) {
k=0;
break;
}
else
}
if (k==1) {
rowPassOne();
}
}
if (x==i) {
rowPassOne();
}
}
if (k==2){
if (y0==y) {
remove();
}
if (y0y) {
for (n=y0;n=y-1 ;n++ ) {
if (grid[i][n]!=0) {
k=0;
break;
}
if(grid[i][n]==0 n==y-1) {
remove();
}
}
}
if (y0y) {
for (n=y0;n=y+1 ;n--) {
if (grid[i][n]!=0) {
k=0;
break;
}
if(grid[i][n]==0 n==y+1) {
remove();
}
}
}
}
}
}
}
public void linePassOne(){
if (y0j){ //第一按钮同行空按钮在左边
for (i=y0-1;i=j ;i-- ){ //判断第一按钮同左侧空按钮之间有没按钮
if (grid[x0][i]!=0) {
k=0;
break;
}
else //K=2说明通过了第二次验证
}
}
if (y0j){ //第一按钮同行空按钮在与第二按钮之间
for (i=y0+1;i=j ;i++){
if (grid[x0][i]!=0) {
k=0;
break;
}
else
}
}
}
public void rowPassOne(){
if (x0i) {
for (j=x0-1;j=i ;j-- ) {
if (grid[j][y0]!=0) {
k=0;
break;
}
else
}
}
if (x0i) {
for (j=x0+1;j=i ;j++ ) {
if (grid[j][y0]!=0) {
k=0;
break;
}
else
}
}
}
public void remove(){
firstButton.setVisible(false);
secondButton.setVisible(false);
fraction();
pressInformation=false;
k=0;
grid[x0][y0]=0;
grid[x][y]=0;
}
public void actionPerformed(ActionEvent e) {
if(e.getSource()==newlyButton){
int grid[][] = new int[8][7];
this.grid = grid;
randomBuild();
mainFrame.setVisible(false);
pressInformation=false;
init();
}
if(e.getSource()==exitButton)
System.exit(0);
if(e.getSource()==resetButton)
reload();
for(int cols = 0;cols 6;cols++){
for(int rows = 0;rows 5;rows++ ){
if(e.getSource()==diamondsButton[cols][rows])
estimateEven(cols+1,rows+1,diamondsButton[cols][rows]);
}
}
}
public static void main(String[] args) {
lianliankan llk = new lianliankan();
llk.randomBuild();
llk.init();
}
}
//old 998 lines
//new 318 lines
相关问答
Q1: java二叉树家谱实现
mport java.awt.BorderLayout;
import java.awt.Dimension;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.util.Random;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.JScrollPane;
import javax.swing.JTree;
import javax.swing.tree.DefaultMutableTreeNode;
public class Randomtree extends JFrame {
private JTree tree;
public static String[] school = { "初中课程", "高中课程", "大学课程" };
public static String[] color = { "颜色", "运动", "食物" };
public static String[] plant = { "植物", "动物", "人" };
public static String[][] school2= {
{ "初中一年级", "初中二年级", "初中三年级"}, {"高中一年级", "高中二年级",
"高中三年级"}, {"大学一年级", "大学二年级", "大学三年级", "大学四年级"} };
public static String[][] color2 = {
{ "绿色", "白色", "红色"}, {"足球", "篮球",
"羽毛球"}, {"面包", "牛奶", "披萨", "热狗"} };
public static String[][] plant2 = {
{ "玫瑰花", "月季花", "海棠花"}, {"猪", "狗",
"猫"}, {"黄种人", "黑种人", "白种人", } };
public static void main(String[] args) {
// TODO 自动生成方法存根
new Randomtree();
}
public Randomtree() {
super();
final Random random=new Random();
setVisible(true);
setSize(300,400);
tree = new JTree();
final JPanel panel = new JPanel();
panel.setPreferredSize(new Dimension(0, 40));
getContentPane().add(panel, BorderLayout.NORTH);
final JScrollPane scrollPane = new JScrollPane();
scrollPane.setPreferredSize(new Dimension(300, 350));
getContentPane().add(scrollPane, BorderLayout.CENTER);
final JButton button = new JButton();
button.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent arg0) {
int k=random.nextInt(3);
tree=getTree(k);
scrollPane.setViewportView(tree);
}
});
scrollPane.setViewportView(null);
button.setText("随机生成树");
panel.add(button);
pack();
}
protected JTree getTree(int n) {
String[] second=null;
String[][] three=null;
if(n==0){second=school; three=school2;}
if(n==1){second=color; three=color2;}
if(n==2){second=plant; three=plant2;}
DefaultMutableTreeNode root=new DefaultMutableTreeNode("root");
for(int i=0;isecond.length;i++){
DefaultMutableTreeNode secondNode=new DefaultMutableTreeNode(second[i]);
for (int j=0;jthree[i].length;j++){
DefaultMutableTreeNode threetNode=new DefaultMutableTreeNode(three[i][j]);
secondNode.add(threetNode);
}
root.add(secondNode);
}
JTree tree=new JTree(root);
tree.expandRow(1);
tree.expandRow(5);
tree.expandRow(9);
return tree;
}
}
简单的 例子你可以模仿一下
Q2: 运用Java数据结构的知识创建树，内容是族谱。
每一个节点有一个成员变量引用下一个节点就行java家谱代码了。
大致实现java家谱代码了一下单向链表 没有加入异常也没有仔细考虑实现java家谱代码的代码java家谱代码的效率java家谱代码，可以参考下。
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public class LinkListTest {
public static void main(String[] args) {
LinkListString ll=new LinkListString();
ll.add("a");
ll.add("b");
ll.add("c");
ll.add("d");
ll.remove(1);
System.out.println(ll.get(0));
System.out.println(ll.get(1));
System.out.println(ll.get(2));
System.out.println(ll.get(3));
System.out.println(ll.size());
}
}
class LinkListT{
private NodeT frist=null;
private NodeT last=null;
private int size=0;
public void add(T t){
if(frist==null){
NodeT node=new NodeT();
node.setT(t);
size++;
frist=node;
last=node;
}else{
NodeT node=new NodeT();
node.setT(t);
last.setNextNode(node);
size++;
last=node;
}
}
public T get(int i){
if(i=0isize){
NodeT nod=null;
for(int n=0;n=i;n++){
if(n==0)
nod=frist;
else
nod=nod.getNextNode();
if(i==n){
return nod.getT();
}
}
}
return null;
}
public void remove(int i){
if(i=0isize){
if(size2){
frist=null;
last=null;
size=0;
}else{
size--;
if(i==0){
frist=frist.getNextNode();
}else{
NodeT nod1=null;
NodeT nod2=null;
for(int n=0;n=i;n++){
if(n==0){
nod1=frist;
nod2=frist;
}else{
nod2=nod1;
nod1=nod1.getNextNode();
}
if(i==n){
if(nod1!=null)
nod2.setNextNode(nod1.getNextNode());
else{
nod2.setNextNode(null);
last=nod2;
}
}
}
}
}
}
}
public int size(){
return size;
}
}
class Node T{
public T getT() {
return t;
}
public void setT(T t) {
this.t = t;
}
public NodeT getNextNode() {
return nextNode;
}
public void setNextNode(NodeT nextNode) {
this.nextNode = nextNode;
}
private T t;
private NodeT nextNode=null;
}
java家谱代码的介绍就聊到这里吧，感谢你花时间阅读本站内容，更多关于java家族的姓氏、java家谱代码的信息别忘了在本站进行查找喔。
