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java中排序算法代码
package temp;
import sun.misc.Sort;
/**
* @author zengjl
* @version 1.0
* @since 2007-08-22
* @Des java几种基本排序方法
*/
/**
* SortUtil:排序方法
* 关于对排序方法算法代码java的选择:这告诉我们算法代码java,什么时候用什么排序最好。当人们渴望先知道排在前面算法代码java的是谁时算法代码java,
* 我们用选择排序;当我们不断拿到新的数并想保持已有的数始终有序时,我们用插入排序;当给出的数
* 列已经比较有序,只需要小幅度的调整一下时,我们用冒泡排序。
*/
public class SortUtil extends Sort {
/**
* 插入排序法
* @param data
* @Des 插入排序(Insertion Sort)是,每次从数列中取一个还没有取出过的数,并按照大小关系插入到已经取出的数中使得已经取出的数仍然有序。
*/
public int[] insertSort(int[] data) {
1/11页
int temp;
for (int i = 1; i data.length; i++) {
for (int j = i; (j 0) (data[j] data[j - 1]); j--) {
swap(data, j, j - 1);
}
}
return data;
}
/**
* 冒泡排序法
* @param data
* @return
* @Des 冒泡排序(Bubble Sort)分为若干趟进行,每一趟排序从前往后比较每两个相邻的元素的大小(因此一趟排序要比较n-1对位置相邻的数)并在
* 每次发现前面的那个数比紧接它后的数大时交换位置;进行足够多趟直到某一趟跑完后发现这一趟没有进行任何交换操作(最坏情况下要跑n-1趟,
* 这种情况在最小的数位于给定数列的最后面时发生)。事实上,在第一趟冒泡结束后,最后面那个数肯定是最大的算法代码java了,于是第二次只需要对前面n-1
* 个数排序,这又将把这n-1个数中最小的数放到整个数列的倒数第二个位置。这样下去,冒泡排序第i趟结束后后面i个数都已经到位了,第i+1趟实
* 际上只考虑前n-i个数(需要的比较次数比前面所说的n-1要小)。这相当于用数学归纳法证明了冒泡排序的正确性
相关问答
Q1: java中希尔排序算法代码
public class ShellSort {
//交换数组元素
private static void swap(int[] a, int i, int j) {
int t = a[i];
a[i] = a[j];
a[j] = t;
}
public static void sort(int[] a) {
int h = 1;
while (h a.length / 3) {//寻找合适的间隔h
h = 3 * h + 1;
}
while (h = 1) {
//将数组变为间隔h个元素有序
for (int i = h; i a.length; i++) {
//间隔h插入排序
for (int j = i; j = h a[j] a[j - h]; j -= h) {
swap(a, j, j - h);
}
}
h /= 3;
}
}
}
Q2: java的md5的加密算法代码
import java.lang.reflect.*;
/*******************************************************************************
* keyBean 类实现了RSA Data Security, Inc.在提交给IETF 的RFC1321中的keyBean message-digest
* 算法。
******************************************************************************/
public class keyBean {
/*
* 下面这些S11-S44实际上是一个4*4的矩阵,在原始的C实现中是用#define 实现的, 这里把它们实现成为static
* final是表示了只读,切能在同一个进程空间内的多个 Instance间共享
*/
static final int S11 = 7;
static final int S12 = 12;
static final int S13 = 17;
static final int S14 = 22;
static final int S21 = 5;
static final int S22 = 9;
static final int S23 = 14;
static final int S24 = 20;
static final int S31 = 4;
static final int S32 = 11;
static final int S33 = 16;
static final int S34 = 23;
static final int S41 = 6;
static final int S42 = 10;
static final int S43 = 15;
static final int S44 = 21;
static final byte[] PADDING = { -128, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0 };
/*
* 下面的三个成员是keyBean计算过程中用到的3个核心数据,在原始的C实现中 被定义到keyBean_CTX结构中
*/
private long[] state = new long[4]; // state (ABCD)
private long[] count = new long[2]; // number of bits, modulo 2^64 (lsb
// first)
private byte[] buffer = new byte[64]; // input buffer
/*
* digestHexStr是keyBean的唯一一个公共成员,是最新一次计算结果的 16进制ASCII表示.
*/
public String digestHexStr;
/*
* digest,是最新一次计算结果的2进制内部表示,表示128bit的keyBean值.
*/
private byte[] digest = new byte[16];
/*
* getkeyBeanofStr是类keyBean最主要的公共方法,入口参数是你想要进行keyBean变换的字符串
* 返回的是变换完的结果,这个结果是从公共成员digestHexStr取得的.
*/
public String getkeyBeanofStr(String inbuf) {
keyBeanInit();
keyBeanUpdate(inbuf.getBytes(), inbuf.length());
keyBeanFinal();
digestHexStr = "";
for (int i = 0; i 16; i++) {
digestHexStr += byteHEX(digest[i]);
}
return digestHexStr;
}
// 这是keyBean这个类的标准构造函数,JavaBean要求有一个public的并且没有参数的构造函数
public keyBean() {
keyBeanInit();
return;
}
/* keyBeanInit是一个初始化函数,初始化核心变量,装入标准的幻数 */
private void keyBeanInit() {
count[0] = 0L;
count[1] = 0L;
// /* Load magic initialization constants.
state[0] = 0x67452301L;
state[1] = 0xefcdab89L;
state[2] = 0x98badcfeL;
state[3] = 0x10325476L;
return;
}
/*
* F, G, H ,I 是4个基本的keyBean函数,在原始的keyBean的C实现中,由于它们是
* 简单的位运算,可能出于效率的考虑把它们实现成了宏,在java中,我们把它们 实现成了private方法,名字保持了原来C中的。
*/
private long F(long x, long y, long z) {
return (x y) | ((~x) z);
}
private long G(long x, long y, long z) {
return (x z) | (y (~z));
}
private long H(long x, long y, long z) {
return x ^ y ^ z;
}
private long I(long x, long y, long z) {
return y ^ (x | (~z));
}
/*
* FF,GG,HH和II将调用F,G,H,I进行近一步变换 FF, GG, HH, and II transformations for
* rounds 1, 2, 3, and 4. Rotation is separate from addition to prevent
* recomputation.
*/
private long FF(long a, long b, long c, long d, long x, long s, long ac) {
a += F(b, c, d) + x + ac;
a = ((int) a s) | ((int) a (32 - s));
a += b;
return a;
}
private long GG(long a, long b, long c, long d, long x, long s, long ac) {
a += G(b, c, d) + x + ac;
a = ((int) a s) | ((int) a (32 - s));
a += b;
return a;
}
private long HH(long a, long b, long c, long d, long x, long s, long ac) {
a += H(b, c, d) + x + ac;
a = ((int) a s) | ((int) a (32 - s));
a += b;
return a;
}
private long II(long a, long b, long c, long d, long x, long s, long ac) {
a += I(b, c, d) + x + ac;
a = ((int) a s) | ((int) a (32 - s));
a += b;
return a;
}
/*
* keyBeanUpdate是keyBean的主计算过程,inbuf是要变换的字节串,inputlen是长度,这个
* 函数由getkeyBeanofStr调用,调用之前需要调用keyBeaninit,因此把它设计成private的
*/
private void keyBeanUpdate(byte[] inbuf, int inputLen) {
int i, index, partLen;
byte[] block = new byte[64];
index = (int) (count[0] 3) 0x3F;
// /* Update number of bits */
if ((count[0] += (inputLen 3)) (inputLen 3))
count[1]++;
count[1] += (inputLen 29);
partLen = 64 - index;
// Transform as many times as possible.
if (inputLen = partLen) {
keyBeanMemcpy(buffer, inbuf, index, 0, partLen);
keyBeanTransform(buffer);
for (i = partLen; i + 63 inputLen; i += 64) {
keyBeanMemcpy(block, inbuf, 0, i, 64);
keyBeanTransform(block);
}
index = 0;
} else
i = 0;
// /* Buffer remaining input */
keyBeanMemcpy(buffer, inbuf, index, i, inputLen - i);
}
/*
* keyBeanFinal整理和填写输出结果
*/
private void keyBeanFinal() {
byte[] bits = new byte[8];
int index, padLen;
// /* Save number of bits */
Encode(bits, count, 8);
// /* Pad out to 56 mod 64.
index = (int) (count[0] 3) 0x3f;
padLen = (index 56) ? (56 - index) : (120 - index);
keyBeanUpdate(PADDING, padLen);
// /* Append length (before padding) */
keyBeanUpdate(bits, 8);
// /* Store state in digest */
Encode(digest, state, 16);
}
/*
* keyBeanMemcpy是一个内部使用的byte数组的块拷贝函数,从input的inpos开始把len长度的
* 字节拷贝到output的outpos位置开始
*/
private void keyBeanMemcpy(byte[] output, byte[] input, int outpos,
int inpos, int len) {
int i;
for (i = 0; i len; i++)
output[outpos + i] = input[inpos + i];
}
/*
* keyBeanTransform是keyBean核心变换程序,有keyBeanUpdate调用,block是分块的原始字节
*/
private void keyBeanTransform(byte block[]) {
long a = state[0], b = state[1], c = state[2], d = state[3];
long[] x = new long[16];
Decode(x, block, 64);
/* Round 1 */
a = FF(a, b, c, d, x[0], S11, 0xd76aa478L); /* 1 */
d = FF(d, a, b, c, x[1], S12, 0xe8c7b756L); /* 2 */
c = FF(c, d, a, b, x[2], S13, 0x242070dbL); /* 3 */
b = FF(b, c, d, a, x[3], S14, 0xc1bdceeeL); /* 4 */
a = FF(a, b, c, d, x[4], S11, 0xf57c0fafL); /* 5 */
d = FF(d, a, b, c, x[5], S12, 0x4787c62aL); /* 6 */
c = FF(c, d, a, b, x[6], S13, 0xa8304613L); /* 7 */
b = FF(b, c, d, a, x[7], S14, 0xfd469501L); /* 8 */
a = FF(a, b, c, d, x[8], S11, 0x698098d8L); /* 9 */
d = FF(d, a, b, c, x[9], S12, 0x8b44f7afL); /* 10 */
c = FF(c, d, a, b, x[10], S13, 0xffff5bb1L); /* 11 */
b = FF(b, c, d, a, x[11], S14, 0x895cd7beL); /* 12 */
a = FF(a, b, c, d, x[12], S11, 0x6b901122L); /* 13 */
d = FF(d, a, b, c, x[13], S12, 0xfd987193L); /* 14 */
c = FF(c, d, a, b, x[14], S13, 0xa679438eL); /* 15 */
b = FF(b, c, d, a, x[15], S14, 0x49b40821L); /* 16 */
/* Round 2 */
a = GG(a, b, c, d, x[1], S21, 0xf61e2562L); /* 17 */
d = GG(d, a, b, c, x[6], S22, 0xc040b340L); /* 18 */
c = GG(c, d, a, b, x[11], S23, 0x265e5a51L); /* 19 */
b = GG(b, c, d, a, x[0], S24, 0xe9b6c7aaL); /* 20 */
a = GG(a, b, c, d, x[5], S21, 0xd62f105dL); /* 21 */
d = GG(d, a, b, c, x[10], S22, 0x2441453L); /* 22 */
c = GG(c, d, a, b, x[15], S23, 0xd8a1e681L); /* 23 */
b = GG(b, c, d, a, x[4], S24, 0xe7d3fbc8L); /* 24 */
a = GG(a, b, c, d, x[9], S21, 0x21e1cde6L); /* 25 */
d = GG(d, a, b, c, x[14], S22, 0xc33707d6L); /* 26 */
c = GG(c, d, a, b, x[3], S23, 0xf4d50d87L); /* 27 */
b = GG(b, c, d, a, x[8], S24, 0x455a14edL); /* 28 */
a = GG(a, b, c, d, x[13], S21, 0xa9e3e905L); /* 29 */
d = GG(d, a, b, c, x[2], S22, 0xfcefa3f8L); /* 30 */
c = GG(c, d, a, b, x[7], S23, 0x676f02d9L); /* 31 */
b = GG(b, c, d, a, x[12], S24, 0x8d2a4c8aL); /* 32 */
/* Round 3 */
a = HH(a, b, c, d, x[5], S31, 0xfffa3942L); /* 33 */
d = HH(d, a, b, c, x[8], S32, 0x8771f681L); /* 34 */
c = HH(c, d, a, b, x[11], S33, 0x6d9d6122L); /* 35 */
b = HH(b, c, d, a, x[14], S34, 0xfde5380cL); /* 36 */
a = HH(a, b, c, d, x[1], S31, 0xa4beea44L); /* 37 */
d = HH(d, a, b, c, x[4], S32, 0x4bdecfa9L); /* 38 */
c = HH(c, d, a, b, x[7], S33, 0xf6bb4b60L); /* 39 */
b = HH(b, c, d, a, x[10], S34, 0xbebfbc70L); /* 40 */
a = HH(a, b, c, d, x[13], S31, 0x289b7ec6L); /* 41 */
d = HH(d, a, b, c, x[0], S32, 0xeaa127faL); /* 42 */
c = HH(c, d, a, b, x[3], S33, 0xd4ef3085L); /* 43 */
b = HH(b, c, d, a, x[6], S34, 0x4881d05L); /* 44 */
a = HH(a, b, c, d, x[9], S31, 0xd9d4d039L); /* 45 */
d = HH(d, a, b, c, x[12], S32, 0xe6db99e5L); /* 46 */
c = HH(c, d, a, b, x[15], S33, 0x1fa27cf8L); /* 47 */
b = HH(b, c, d, a, x[2], S34, 0xc4ac5665L); /* 48 */
/* Round 4 */
a = II(a, b, c, d, x[0], S41, 0xf4292244L); /* 49 */
d = II(d, a, b, c, x[7], S42, 0x432aff97L); /* 50 */
c = II(c, d, a, b, x[14], S43, 0xab9423a7L); /* 51 */
b = II(b, c, d, a, x[5], S44, 0xfc93a039L); /* 52 */
a = II(a, b, c, d, x[12], S41, 0x655b59c3L); /* 53 */
d = II(d, a, b, c, x[3], S42, 0x8f0ccc92L); /* 54 */
c = II(c, d, a, b, x[10], S43, 0xffeff47dL); /* 55 */
b = II(b, c, d, a, x[1], S44, 0x85845dd1L); /* 56 */
a = II(a, b, c, d, x[8], S41, 0x6fa87e4fL); /* 57 */
d = II(d, a, b, c, x[15], S42, 0xfe2ce6e0L); /* 58 */
c = II(c, d, a, b, x[6], S43, 0xa3014314L); /* 59 */
b = II(b, c, d, a, x[13], S44, 0x4e0811a1L); /* 60 */
a = II(a, b, c, d, x[4], S41, 0xf7537e82L); /* 61 */
d = II(d, a, b, c, x[11], S42, 0xbd3af235L); /* 62 */
c = II(c, d, a, b, x[2], S43, 0x2ad7d2bbL); /* 63 */
b = II(b, c, d, a, x[9], S44, 0xeb86d391L); /* 64 */
state[0] += a;
state[1] += b;
state[2] += c;
state[3] += d;
}
/*
* Encode把long数组按顺序拆成byte数组,因为java的long类型是64bit的, 只拆低32bit,以适应原始C实现的用途
*/
private void Encode(byte[] output, long[] input, int len) {
int i, j;
for (i = 0, j = 0; j len; i++, j += 4) {
output[j] = (byte) (input[i] 0xffL);
output[j + 1] = (byte) ((input[i] 8) 0xffL);
output[j + 2] = (byte) ((input[i] 16) 0xffL);
output[j + 3] = (byte) ((input[i] 24) 0xffL);
}
}
/*
* Decode把byte数组按顺序合成成long数组,因为java的long类型是64bit的,
* 只合成低32bit,高32bit清零,以适应原始C实现的用途
*/
private void Decode(long[] output, byte[] input, int len) {
int i, j;
for (i = 0, j = 0; j len; i++, j += 4)
output[i] = b2iu(input[j]) | (b2iu(input[j + 1]) 8)
| (b2iu(input[j + 2]) 16) | (b2iu(input[j + 3]) 24);
return;
}
/*
* b2iu是我写的一个把byte按照不考虑正负号的原则的”升位”程序,因为java没有unsigned运算
*/
public static long b2iu(byte b) {
return b 0 ? b 0x7F + 128 : b;
}
/*
* byteHEX(),用来把一个byte类型的数转换成十六进制的ASCII表示,
* 因为java中的byte的toString无法实现这一点,我们又没有C语言中的 sprintf(outbuf,"%02X",ib)
*/
public static String byteHEX(byte ib) {
char[] Digit = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A',
'B', 'C', 'D', 'E', 'F' };
char[] ob = new char[2];
ob[0] = Digit[(ib 4) 0X0F];
ob[1] = Digit[ib 0X0F];
String s = new String(ob);
return s;
}
public static void main(String args[]) {
keyBean m = new keyBean();
if (Array.getLength(args) == 0) { // 如果没有参数,执行标准的Test Suite
System.out.println("keyBean Test suite:");
System.out.println("keyBean(\"):" + m.getkeyBeanofStr(""));
System.out.println("keyBean(\"a\"):" + m.getkeyBeanofStr("a"));
System.out.println("keyBean(\"abc\"):" + m.getkeyBeanofStr("abc"));
System.out.println("keyBean(\"message digest\"):"
+ m.getkeyBeanofStr("message digest"));
System.out.println("keyBean(\"abcdefghijklmnopqrstuvwxyz\"):"
+ m.getkeyBeanofStr("abcdefghijklmnopqrstuvwxyz"));
System.out
.println("keyBean(\"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789\"):"
+ m
.getkeyBeanofStr("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789"));
} else
System.out.println("keyBean(" + args[0] + ")="
+ m.getkeyBeanofStr(args[0]));
}
}
Q3: 关于各种排列组合java算法实现方法
一 利用二进制状态法求排列组合 此种方法比较容易懂 但是运行效率不高 小数据排列组合可以使用
复制代码 代码如下: import java util Arrays;
//利用二进制算法进行全排列 //count : //count :
public class test { public static void main(String[] args) { long start=System currentTimeMillis(); count (); long end=System currentTimeMillis(); System out println(end start); } private static void count (){ int[] num=new int []{ }; for(int i= ;iMath pow( );i++){ String str=Integer toString(i ); int sz=str length(); for(int j= ;j sz;j++){ str=" "+str; } char[] temp=str toCharArray(); Arrays sort(temp); String gl=new String(temp); if(!gl equals(" ")){ continue; } String result=""; for(int m= ;mstr length();m++){ result+=num[Integer parseInt(str charAt(m)+"")]; } System out println(result); } } public static void count (){ int[] num=new int []{ }; int[] ss=new int []{ }; int[] temp=new int[ ]; while(temp[ ] ){ temp[temp length ]++; for(int i=temp length ;i ;i ){ if(temp[i]== ){ temp[i]= ; temp[i ]++; } } int []tt=temp clone(); Arrays sort(tt); if(!Arrays equals(tt ss)){ continue; } String result=""; for(int i= ;inum length;i++){ result+=num[temp[i]]; } System out println(result); } } }
二 用递归算法代码java的思想来求排列跟组合 代码量比较大
复制代码 代码如下: package practice;
import java util ArrayList; import java util List;
public class Test {
/** * @param args */ public static void main(String[] args) { // TODO Auto generated method stub Object[] tmp={ }; // ArrayListObject[] rs=RandomC(tmp); ArrayListObject[] rs=cmn(tmp ); for(int i= ;irs size();i++) { // System out print(i+"="); for(int j= ;jrs get(i) length;j++) { System out print(rs get(i)[j]+" "); } System out println(); } }
// 求一个数组算法代码java的任意组合 static ArrayListObject[] RandomC(Object[] source) { ArrayListObject[] result=new ArrayListObject[](); if(source length== ) { result add(source); } else { Object[] psource=new Object[source length ]; for(int i= ;ipsource length;i++) { psource[i]=source[i]; } result=RandomC(psource); int len=result size();//fn组合的长度 result add((new Object[]{source[source length ]})); for(int i= ;ilen;i++) { Object[] tmp=new Object[result get(i) length+ ]; for(int j= ;jtmp length ;j++) { tmp[j]=result get(i)[j]; } tmp[tmp length ]=source[source length ]; result add(tmp); } } return result; } static ArrayListObject[] cmn(Object[] source int n) { ArrayListObject[] result=new ArrayListObject[](); if(n== ) { for(int i= ;isource length;i++) { result add(new Object[]{source[i]}); } } else if(source length==n) { result add(source); } else { Object[] psource=new Object[source length ]; for(int i= ;ipsource length;i++) { psource[i]=source[i]; } result=cmn(psource n); ArrayListObject[] tmp=cmn(psource n ); for(int i= ;itmp size();i++) { Object[] rs=new Object[n]; for(int j= ;jn ;j++) { rs[j]=tmp get(i)[j]; } rs[n ]=source[source length ]; result add(rs); } } return result; }
}
三 利用动态规划的思想求排列和组合
复制代码 代码如下: package Acm; //强大的求组合数 public class MainApp { public static void main(String[] args) { int[] num=new int[]{ }; String str=""; //求 个数的组合个数 // count( str num ); // 求 n个数的组合个数 count ( str num); }
private static void count (int i String str int[] num) { if(i==num length){ System out println(str); return; } count (i+ str num); count (i+ str+num[i]+" " num); }
private static void count(int i String str int[] num int n) { if(n== ){ System out println(str); return; } if(i==num length){ return; } count(i+ str+num[i]+" " num n ); count(i+ str num n); } }
下面是求排列
复制代码 代码如下: lishixinzhi/Article/program/Java/JSP/201311/20148
Q4: JAVA 编程,算法,详细在图里, 求代码、详细解答?
(a)It is insert sort algorithm of the above code segment.上面的代码是插入排序算法
(b)
EXAMPLE
AEXMPLE
AEMXPLE
AEMPXLE
AELMPXE
AEELMPX
(c)
Require 6 sorting steps.
补充完整的插入排序算法的Java程序如下
public class A{
public static void main(String[] args){
char[] a={'E','X','A','M','P','L','E'};
char v;
int i,j,n=a.length,count=0;
for (i =1; i n; i++){
v = a[i];
j = i;
while(j 0 a[j-1] v) {
a[j] = a[j-1];
j--;
}
a[j] = v;
count++;
System.out.println(new String(a));
}
System.out.println("Require "+count+" sorting steps.");
}
}
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