java连连看代码素材 java连连看完整源代码

求连连看源代码

连连看的代码（基本算法）加了部分注释

import java.awt.*;

import java.awt.event.*;

public class lianliankan implements ActionListener

{

static String s="no"; //用来纪录点击按钮的信息

int x0=0,y0=0,x=0,y=0,n1=0,n2=0; //用来纪录按钮的位置信息

Frame f,f1;

Button b1,b2,b3,b4,b5,b6,b7,b8,b9,b10; //用比较笨的方法添加了

Button b11,b12,b13,b14,b15,b16,b17,b18; //30个按钮来实现游戏界面

Button b19,b20,b21,b22,b23,b24,b25; //可以用数组实现，这是本人

Button b26,b27,b28,b29,b30,bc; //学java时，入门的联系，所以

Button b,ba,br,bt1,bt2; //有些东西很业余！！嘻嘻

Panel p1,p2,p3;

TextField t; //用来显示一些随机信息，方法是下面的guli().

Label l;

int d[][]={ //用来和界面的按钮建立映射关系

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0}

};

public static void main(String[] args)

{

lianliankan t=new lianliankan();

t.suiji();

t.go();

}

public void actionPerformed(ActionEvent e) //再来一次按钮的响应事件。

{

int d[][]={

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0}

};

this.d=d;

suiji();

f.setVisible(false);

f1.setVisible(false);

s="no";

go();

}

public void go()//初始化界面

{

l=new Label("亲爱的玩家，");

f=new Frame("连连看");

t=new TextField();

p2=new Panel();

p1=new Panel();

p3=new Panel();

bc=new Button("退出");

br=new Button("重列");

b=new Button();

b1=new Button(String.valueOf(d[1][1]));

b2=new Button(String.valueOf(d[1][2]));

b3=new Button(String.valueOf(d[1][3]));

b4=new Button(String.valueOf(d[1][4]));

b5=new Button(String.valueOf(d[1][5]));

b6=new Button(String.valueOf(d[2][1]));

b7=new Button(String.valueOf(d[2][2]));

b8=new Button(String.valueOf(d[2][3]));

b9=new Button(String.valueOf(d[2][4]));

b10=new Button(String.valueOf(d[2][5]));

b11=new Button(String.valueOf(d[3][1]));

b12=new Button(String.valueOf(d[3][2]));

b13=new Button(String.valueOf(d[3][3]));

b14=new Button(String.valueOf(d[3][4]));

b15=new Button(String.valueOf(d[3][5]));

b16=new Button(String.valueOf(d[4][1]));

b17=new Button(String.valueOf(d[4][2]));

b18=new Button(String.valueOf(d[4][3]));

b19=new Button(String.valueOf(d[4][4]));

b20=new Button(String.valueOf(d[4][5]));

b21=new Button(String.valueOf(d[5][1]));

b22=new Button(String.valueOf(d[5][2]));

b23=new Button(String.valueOf(d[5][3]));

b24=new Button(String.valueOf(d[5][4]));

b25=new Button(String.valueOf(d[5][5]));

b26=new Button(String.valueOf(d[6][1]));

b27=new Button(String.valueOf(d[6][2]));

b28=new Button(String.valueOf(d[6][3]));

b29=new Button(String.valueOf(d[6][4]));

b30=new Button(String.valueOf(d[6][5]));

p3.setLayout(null);

p1.setSize(250,300);

p2.setSize(100,40);

p3.setSize(300,30);

t.setSize(60,30);

l.setSize(70,30);

p1.setLayout(new GridLayout(6,5));

p1.setBackground(Color.pink);

p1.setLocation(100,100);

p2.setLocation(0,400);

p3.setLocation(50,50);

t.setLocation(230,2);

l.setLocation(150,2);

bc.setLocation(0,40);

br.setLocation(0,100);

f.add(p1);

f.add(p2);

f.add(p3);

p3.add(l);

p3.add(t);

p2.add(bc);

p2.add(br);

p1.add(b1);

p1.add(b2);

p1.add(b3);

p1.add(b4);

p1.add(b5);

p1.add(b6);

p1.add(b7);

p1.add(b8);

p1.add(b9);

p1.add(b10);

p1.add(b11);

p1.add(b12);

p1.add(b13);

p1.add(b14);

p1.add(b15);

p1.add(b16);

p1.add(b17);

p1.add(b18);

p1.add(b19);

p1.add(b20);

p1.add(b21);

p1.add(b22);

p1.add(b23);

p1.add(b24);

p1.add(b25);

p1.add(b26);

p1.add(b27);

p1.add(b28);

p1.add(b29);

p1.add(b30);

f.pack();

f.setBounds(280,100,500,450);

f.setResizable(false);

f.setVisible(true);

bc.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

ex();

}

});

br.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

chonglie();

}

});

b1.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(1,1,b1);

}

});

b2.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(1,2,b2);

}

});

b3.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(1,3,b3);

}

});

b4.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(1,4,b4);

}

});

b5.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(1,5,b5);

}

});

b6.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(2,1,b6);

}

});

b7.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(2,2,b7);

}

});

b8.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(2,3,b8);

}

});

b9.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(2,4,b9);

}

});

b10.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(2,5,b10);

}

});

b11.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(3,1,b11);

}

});

b12.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(3,2,b12);

}

});

b13.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(3,3,b13);

}

});

b14.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(3,4,b14);

}

});

b15.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(3,5,b15);

}

});

b16.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(4,1,b16);

}

});

b17.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(4,2,b17);

}

});

b18.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(4,3,b18);

}

});

b19.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(4,4,b19);

}

});

b20.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(4,5,b20);

}

});

b21.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(5,1,b21);

}

});

b22.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(5,2,b22);

}

});

b23.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(5,3,b23);

}

});

b24.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(5,4,b24);

}

});

b25.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(5,5,b25);

}

});

b26.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(6,1,b26);

}

});

b27.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(6,2,b27);

}

});

b28.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(6,3,b28);

}

});

b29.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(6,4,b29);

}

});

b30.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

wei(6,5,b30);

}

});

}

public void ex() //退出界面，可用diolog来实现有模式的类型，更加符合

{

f1=new Frame("游戏作业");

f1.setLayout(new GridLayout(1,1));

bt1=new Button("确定退出");

bt2=new Button("再来一局");

f1.add(bt1);

f1.add(bt2);

f1.pack();

f1.setBounds(400,250,90,60);

f1.setResizable(false);

f1.show();

f1.setVisible(true);

bt1.addMouseListener(new MouseAdapter(){

public void mouseClicked(MouseEvent e)

{

System.exit(0);

}

});

bt2.addActionListener(this);

}

public void suiji() //产生随机数，来填充游戏界面对应的数组的各个位置

{

int m,n,k=0,k1,k2,k3;

for(m=1;m=15;m++)

{

k1=(int)(Math.random()*25+1);

for(n=1;n=2;n++)

{

k2=(int)(Math.random()*6+1);

k3=(int)(Math.random()*5+1);

while(d[k2][k3]!=0 k!=30)

{

k2=(int)(Math.random()*6+1);

k3=(int)(Math.random()*5+1);

}

this.d[k2][k3]=k1;

k++;

}

}

}

public void guli() //随机信息

{

int l=0;

t.setText("");

l=(int)(Math.random()*10);

System.out.println(l);

switch(l)

{

case 1:

t.setText("好！加油！");

break;

case 3:

t.setText("你真棒！");

break;

case 5:

t.setText("加快速度！");

break;

case 6:

t.setText("不错啊！");

break;

case 8:

t.setText("加油吧！");

break;

case 9:

t.setText("够聪明!");

break;

default:

break;

}

}

public void chonglie() //重列方法

{

int save[],i,j,n=0,k2,k3,k;

int d[][]={

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0},

{0,0,0,0,0,0,0}

};

save=new int[30];

for(n=0;n30;n++)

save[n]=0; //定义一个数组来保存当前的每个按钮位置上的信息

n=0;

for(i=0;i=6;i++)

for(j=0;j=5;j++)

{

if(this.d[i][j]!=0)

{

save[n]=this.d[i][j];

n++;

}

}

n=n-1;

this.d=d;

while(n=0) //产生随机位置，放置按钮

{

k2=(int)(Math.random()*6+1);

k3=(int)(Math.random()*5+1);

while(d[k2][k3]!=0)

{

k2=(int)(Math.random()*6+1);

k3=(int)(Math.random()*5+1);

}

this.d[k2][k3]=save[n];

n--;

}

f.setVisible(false);

s="no"; //这里一定要将按钮点击信息归为初始

go();

ling();

}

public void ling() //将数组中为零的成员对应的按钮消去

{ //用按钮类型的数组实现会简化得多，

if(d[1][1]==0)

b1.setVisible(false);

if(d[1][2]==0)

b2.setVisible(false);

if(d[1][3]==0)

b3.setVisible(false);

if(d[1][4]==0)

b4.setVisible(false);

if(d[1][5]==0)

b5.setVisible(false);

if(d[2][1]==0)

b6.setVisible(false);

if(d[2][2]==0)

b7.setVisible(false);

if(d[2][3]==0)

b8.setVisible(false);

if(d[2][4]==0)

b9.setVisible(false);

if(d[2][5]==0)

b10.setVisible(false);

if(d[3][1]==0)

b11.setVisible(false);

if(d[3][2]==0)

b12.setVisible(false);

if(d[3][3]==0)

b13.setVisible(false);

if(d[3][4]==0)

b14.setVisible(false);

if(d[3][5]==0)

b15.setVisible(false);

if(d[4][1]==0)

b16.setVisible(false);

if(d[4][2]==0)

b17.setVisible(false);

if(d[4][3]==0)

b18.setVisible(false);

if(d[4][4]==0)

b19.setVisible(false);

if(d[4][5]==0)

b20.setVisible(false);

if(d[5][1]==0)

b21.setVisible(false);

if(d[5][2]==0)

b22.setVisible(false);

if(d[5][3]==0)

b23.setVisible(false);

if(d[5][4]==0)

b24.setVisible(false);

if(d[5][5]==0)

b25.setVisible(false);

if(d[6][1]==0)

b26.setVisible(false);

if(d[6][2]==0)

b27.setVisible(false);

if(d[6][3]==0)

b28.setVisible(false);

if(d[6][4]==0)

b29.setVisible(false);

if(d[6][5]==0)

b30.setVisible(false);

}

public void wei(int w1,int w2,Button bz) //判断并纪录每次点击按钮的信息

{ //当两次的按钮相同才能消去

if((s.trim()).equals("no"))

{

s=b1.getLabel();

x0=w1;

y0=w2;

n1=d[x0][y0];

b=bz;

x=w1;

y=w2;

n2=d[x][y];

ba=bz;

}

else

{

x0=x;

y0=y;

n1=d[x0][y0];

b=ba;

x=w1;

y=w2;

n2=d[x][y];

ba=bz;

if(n1==n2 ba!=b)

{

xiao();

}

}

}

public void xiao() //这里是整个游戏最重要的部分，就是判断两个按钮在信息

{ //相同的情况下能不能消去。仔细分析，不一条条注释

int i=0, j=0,n=0,k=0;

if((x0==x (y0==y+1||y0==y-1)) || ((x0==x+1||x0==x-1)(y0==y))) //相邻的情况

{

ba.setVisible(false);

b.setVisible(false);

guli();

s="no";

d[x0][y0]=0;

d[x][y]=0;

}

else

{

for (j=0;j7;j++ ) //两个按钮按行分析，看能否消去

{

if (d[x0][j]==0)

{

if (yj)

{

for (i=y-1;i=j;i-- )

{

if (d[x][i]!=0)

{

k=0;

break;

}

else

{

k=1;

}

}

if (k==1)

{

if (y0j)

{

for (i=y0-1;i=j ;i-- )

{

if (d[x0][i]!=0)

{

k=0;

break;

}

else

{

k=2;

}

}

}

if (y0j)

{

for (i=y0+1;i=j ;i++)

{

if (d[x0][i]!=0)

{

k=0;

break;

}

else

{

k=2;

}

}

}

}

}

if (yj)

{

for (i=y+1;i=j ;i++ )

{

if (d[x][i]!=0)

{

k=0;

break;

}

else

{

k=1;

}

}

if (k==1)

{

if (y0j)

{

for (i=y0-1;i=j ;i-- )

{

if (d[x0][i]!=0)

{

k=0;

break;

}

else

{

k=2;

}

}

}

if (y0j)

{

for (i=y0+1;i=j ;i++)

{

if (d[x0][i]!=0)

{

k=0;

break;

}

else

{

k=2;

}

}

}

}

}

if (y==j )

{

if (y0j)

{

for (i=y0-1;i=j ;i-- )

{

if (d[x0][i]!=0)

{

k=0;

break;

}

else

{

k=2;

}

}

}

if (y0j)

{

for (i=y0+1;i=j ;i++)

{

if (d[x0][i]!=0)

{

k=0;

break;

}

else

{

k=2;

}

}

}

}

}

if (k==2)

{ if (x0==x)

{

b.setVisible(false);

ba.setVisible(false);

guli();

s="no";

k=0;

d[x0][y0]=0;

d[x][y]=0;

}

if (x0x)

{

for (n=x0;n=x-1;n++ )

{

if (d[n][j]!=0)

{

k=0;

break;

}

if(d[n][j]==0 n==x-1)

{

b.setVisible(false);

ba.setVisible(false);

guli();

s="no";

k=0;

d[x0][y0]=0;

d[x][y]=0;

}

}

}

if (x0x)

{

for (n=x0;n=x+1 ;n-- )

{

if (d[n][j]!=0)

{

k=0;

break;

}

if(d[n][j]==0 n==x+1)

{

b.setVisible(false);

ba.setVisible(false);

guli();

s="no";

k=0;

d[x0][y0]=0;

d[x][y]=0;

}

}

}

}

}

for (i=0;i8;i++ ) //按列分析，看能不能消去

{

if (d[i][y0]==0)

{

if (xi)

{

for (j=x-1;j=i ;j-- )

{

if (d[j][y]!=0)

{

k=0;

break;

}

else

{

k=1;

}

}

if (k==1)

{

if (x0i)

{

for (j=x0-1;j=i ;j-- )

{

if (d[j][y0]!=0)

{

k=0;

break;

}

else

{

k=2;

}

}

}

if (x0i)

{

for (j=x0+1;j=i;j++ )

{

if (d[j][y0]!=0)

{

k=0;

break;

}

else

{

k=2;

}

}

}

}

}

if (xi)

{

for (j=x+1;j=i;j++ )

{

if (d[j][y]!=0)

{

k=0;

break;

}

else

{

k=1;

}

}

if (k==1)

{

if (x0i)

{

for (j=x0-1;j=i ;j-- )

{

if (d[j][y0]!=0)

{

k=0;

break;

}

else

{

k=2;

}

}

}

if (x0i)

{

for (j=x0+1;j=i ;j++ )

{

if (d[j][y0]!=0)

{

k=0;

break;

}

else

{

k=2;

}

}

}

}

}

if (x==i)

{

if (x0i)

{

for (j=x0-1;j=i ;j-- )

{

if (d[j][y0]!=0)

{

k=0;

break;

}

else

{

k=2;

}

}

}

if (x0i)

{

for (j=x0+1;j=i ;j++ )

{

if (d[j][y0]!=0)

{

k=0;

break;

}

else

{

k=2;

}

}

}

}

}

if (k==2)

{

if (y0==y)

{

b.setVisible(false);

ba.setVisible(false);

guli();

s="no";

k=0;

d[x0][y0]=0;

d[x][y]=0;

}

if (y0y)

{

for (n=y0;n=y-1 ;n++ )

{

if (d[i][n]!=0)

{

k=0;

break;

}

if(d[i][n]==0 n==y-1)

{

b.setVisible(false);

ba.setVisible(false);

guli();

s="no";

k=0;

d[x0][y0]=0;

d[x][y]=0;

}

}

}

if (y0y)

{

for (n=y0;n=y+1 ;n--)

{

if (d[i][n]!=0)

{

k=0;

break;

}

if(d[i][n]==0 n==y+1)

{

b.setVisible(false);

ba.setVisible(false);

guli();

s="no";

k=0;

d[x0][y0]=0;

d[x][y]=0;

}

}

}

}

}

}

}

}

相关问答

Q1: 连连看JAVA源代码是什么?

importjavax.swing.*;\x0d\x0aimportjava.awt.*;\x0d\x0aimportjava.awt.event.*;\x0d\x0apublicclasslianliankanimplementsActionListener\x0d\x0a{\x0d\x0aJFramemainFrame;//主面板\x0d\x0aContainerthisContainer;\x0d\x0aJPanelcenterPanel,southPanel,northPanel;//子面板\x0d\x0aJButtondiamondsButton[][]=newJButton[6][5];//游戏按钮数组\x0d\x0aJButtonexitButton,resetButton,newlyButton;//退出，重列，重新开始按钮\x0d\x0aJLabelfractionLable=newJLabel("0");//分数标签\x0d\x0aJButtonfirstButton,secondButton;//分别记录两次被选中的按钮\x0d\x0aintgrid[][]=newint[8][7];//储存游戏按钮位置\x0d\x0astaticbooleanpressInformation=false;//判断是否有按钮被选中\x0d\x0aintx0=0,y0=0,x=0,y=0,fristMsg=0,secondMsg=0,validateLV;//游戏按钮的位置坐标\x0d\x0ainti,j,k,n;//消除方法控制\x0d\x0apublicvoidinit(){\x0d\x0amainFrame=newJFrame("JKJ连连看");\x0d\x0athisContainer=mainFrame.getContentPane();\x0d\x0athisContainer.setLayout(newBorderLayout());\x0d\x0acenterPanel=newJPanel();\x0d\x0asouthPanel=newJPanel();\x0d\x0anorthPanel=newJPanel();\x0d\x0athisContainer.add(centerPanel,"Center");\x0d\x0athisContainer.add(southPanel,"South");\x0d\x0athisContainer.add(northPanel,"North");\x0d\x0acenterPanel.setLayout(newGridLayout(6,5));\x0d\x0afor(intcols=0;cols=0){\x0d\x0acols=(int)(Math.random()*6+1);\x0d\x0arows=(int)(Math.random()*5+1);\x0d\x0awhile(grid[cols][rows]!=0){\x0d\x0acols=(int)(Math.random()*6+1);\x0d\x0arows=(int)(Math.random()*5+1);\x0d\x0a}\x0d\x0athis.grid[cols][rows]=save[n];\x0d\x0an--;\x0d\x0a}\x0d\x0amainFrame.setVisible(false);\x0d\x0apressInformation=false;//这里一定要将按钮点击信息归为初始\x0d\x0ainit();\x0d\x0afor(inti=0;ij){//如果第二个按钮的Y坐标大于空按钮的Y坐标说明第一按钮在第二按钮左边\x0d\x0afor(i=y-1;i=j;i--){//判断第二按钮左侧直到第一按钮中间有没有按钮\x0d\x0aif(grid[x][i]!=0){\x0d\x0ak=0;\x0d\x0abreak;\x0d\x0a}\x0d\x0aelse//K=1说明通过了第一次验证\x0d\x0a}\x0d\x0aif(k==1){\x0d\x0alinePassOne();\x0d\x0a}\x0d\x0a}\x0d\x0aif(yx){\x0d\x0afor(n=x0;n=x+1;n--){\x0d\x0aif(grid[n][j]!=0){\x0d\x0ak=0;\x0d\x0abreak;\x0d\x0a}\x0d\x0aif(grid[n][j]==0n==x+1){\x0d\x0aremove();\x0d\x0a}\x0d\x0a}\x0d\x0a}\x0d\x0a}\x0d\x0a}\x0d\x0afor(i=0;ii){\x0d\x0afor(j=x-1;j=i;j--){\x0d\x0aif(grid[j][y]!=0){\x0d\x0ak=0;\x0d\x0abreak;\x0d\x0a}\x0d\x0aelse\x0d\x0a}\x0d\x0aif(k==1){\x0d\x0arowPassOne();\x0d\x0a}\x0d\x0a}\x0d\x0aif(xy){\x0d\x0afor(n=y0;n=y+1;n--){\x0d\x0aif(grid[i][n]!=0){\x0d\x0ak=0;\x0d\x0abreak;\x0d\x0a}\x0d\x0aif(grid[i][n]==0n==y+1){\x0d\x0aremove();\x0d\x0a}\x0d\x0a}\x0d\x0a}\x0d\x0a}\x0d\x0a}\x0d\x0a}\x0d\x0a}\x0d\x0apublicvoidlinePassOne(){\x0d\x0aif(y0j){//第一按钮同行空按钮在左边\x0d\x0afor(i=y0-1;i=j;i--){//判断第一按钮同左侧空按钮之间有没按钮\x0d\x0aif(grid[x0][i]!=0){\x0d\x0ak=0;\x0d\x0abreak;\x0d\x0a}\x0d\x0aelse//K=2说明通过了第二次验证\x0d\x0a}\x0d\x0a}\x0d\x0aif(y0i){\x0d\x0afor(j=x0-1;j=i;j--){\x0d\x0aif(grid[j][y0]!=0){\x0d\x0ak=0;\x0d\x0abreak;\x0d\x0a}\x0d\x0aelse\x0d\x0a}\x0d\x0a}\x0d\x0aif(x0

回答于 2022-12-14

Q2: 求java小游戏源代码

表1. CheckerDrag.java

// CheckerDrag.javaimport java.awt.*;import java.awt.event.*;public class CheckerDrag extends java.applet.Applet{ // Dimension of checkerboard square. // 棋盘上每个小方格的尺寸 final static int SQUAREDIM = 40; // Dimension of checkerboard -- includes black outline. // 棋盘的尺寸 – 包括黑色的轮廓线 final static int BOARDDIM = 8 * SQUAREDIM + 2; // Dimension of checker -- 3/4 the dimension of a square. // 棋子的尺寸 – 方格尺寸的3/4 final static int CHECKERDIM = 3 * SQUAREDIM / 4; // Square colors are dark green or white. // 方格的颜色为深绿色或者白色 final static Color darkGreen = new Color (0, 128, 0); // Dragging flag -- set to true when user presses mouse button over checker // and cleared to false when user releases mouse button. // 拖动标记 --当用户在棋子上按下鼠标按键时设为true， // 释放鼠标按键时设为false boolean inDrag = false; // Left coordinate of checkerboard's upper-left corner. // 棋盘左上角的左方向坐标 int boardx; // Top coordinate of checkerboard's upper-left corner. //棋盘左上角的上方向坐标 int boardy; // Left coordinate of checker rectangle origin (upper-left corner). // 棋子矩形原点(左上角)的左方向坐标 int ox; // Top coordinate of checker rectangle origin (upper-left corner). // 棋子矩形原点(左上角)的上方向坐标 int oy; // Left displacement between mouse coordinates at time of press and checker // rectangle origin. // 在按键时的鼠标坐标与棋子矩形原点之间的左方向位移 int relx; // Top displacement between mouse coordinates at time of press and checker // rectangle origin. // 在按键时的鼠标坐标与棋子矩形原点之间的上方向位移 int rely; // Width of applet drawing area. // applet绘图区域的宽度 int width; // Height of applet drawing area. // applet绘图区域的高度 int height; // Image buffer. // 图像缓冲 Image imBuffer; // Graphics context associated with image buffer. // 图像缓冲相关联的图形背景 Graphics imG; public void init () { // Obtain the size of the applet's drawing area. // 获取applet绘图区域的尺寸 width = getSize ().width; height = getSize ().height; // Create image buffer. // 创建图像缓冲 imBuffer = createImage (width, height); // Retrieve graphics context associated with image buffer. // 取出图像缓冲相关联的图形背景 imG = imBuffer.getGraphics (); // Initialize checkerboard's origin, so that board is centered. // 初始化棋盘的原点，使棋盘在屏幕上居中 boardx = (width - BOARDDIM) / 2 + 1; boardy = (height - BOARDDIM) / 2 + 1; // Initialize checker's rectangle's starting origin so that checker is // centered in the square located in the top row and second column from // the left. // 初始化棋子矩形的起始原点，使得棋子在第一行左数第二列的方格里居中 ox = boardx + SQUAREDIM + (SQUAREDIM - CHECKERDIM) / 2 + 1; oy = boardy + (SQUAREDIM - CHECKERDIM) / 2 + 1; // Attach a mouse listener to the applet. That listener listens for // mouse-button press and mouse-button release events. // 向applet添加一个用来监听鼠标按键的按下和释放事件的鼠标监听器 addMouseListener (new MouseAdapter () { public void mousePressed (MouseEvent e) { // Obtain mouse coordinates at time of press. // 获取按键时的鼠标坐标 int x = e.getX (); int y = e.getY (); // If mouse is over draggable checker at time // of press (i.e., contains (x, y) returns // true), save distance between current mouse // coordinates and draggable checker origin // (which will always be positive) and set drag // flag to true (to indicate drag in progress). // 在按键时如果鼠标位于可拖动的棋子上方 // （也就是contains (x, y)返回true），则保存当前 // 鼠标坐标与棋子的原点之间的距离（始终为正值）并且 // 将拖动标志设为true（用来表明正处在拖动过程中） if (contains (x, y)) { relx = x - ox; rely = y - oy; inDrag = true; } } boolean contains (int x, int y) { // Calculate center of draggable checker. // 计算棋子的中心位置 int cox = ox + CHECKERDIM / 2; int coy = oy + CHECKERDIM / 2; // Return true if (x, y) locates with bounds // of draggable checker. CHECKERDIM / 2 is the // radius. // 如果(x, y)仍处于棋子范围内则返回true // CHECKERDIM / 2为半径 return (cox - x) * (cox - x) + (coy - y) * (coy - y) CHECKERDIM / 2 * CHECKERDIM / 2; } public void mouseReleased (MouseEvent e) { // When mouse is released, clear inDrag (to // indicate no drag in progress) if inDrag is // already set. // 当鼠标按键被释放时，如果inDrag已经为true， // 则将其置为false（用来表明不在拖动过程中） if (inDrag) inDrag = false; } }); // Attach a mouse motion listener to the applet. That listener listens // for mouse drag events. //向applet添加一个用来监听鼠标拖动事件的鼠标运动监听器 addMouseMotionListener (new MouseMotionAdapter () { public void mouseDragged (MouseEvent e) { if (inDrag) { // Calculate draggable checker's new // origin (the upper-left corner of // the checker rectangle). // 计算棋子新的原点（棋子矩形的左上角） int tmpox = e.getX () - relx; int tmpoy = e.getY () - rely; // If the checker is not being moved // (at least partly) off board, // assign the previously calculated // origin (tmpox, tmpoy) as the // permanent origin (ox, oy), and // redraw the display area (with the // draggable checker at the new // coordinates). // 如果棋子（至少是棋子的一部分）没有被 // 移出棋盘，则将之前计算的原点 // (tmpox, tmpoy)赋值给永久性的原点(ox, oy)， // 并且刷新显示区域（此时的棋子已经位于新坐标上） if (tmpox boardx tmpoy boardy tmpox + CHECKERDIM boardx + BOARDDIM tmpoy + CHECKERDIM boardy + BOARDDIM) { ox = tmpox; oy = tmpoy; repaint (); } } } }); } public void paint (Graphics g) { // Paint the checkerboard over which the checker will be dragged. // 在棋子将要被拖动的位置上绘制棋盘 paintCheckerBoard (imG, boardx, boardy); // Paint the checker that will be dragged. // 绘制即将被拖动的棋子 paintChecker (imG, ox, oy); // Draw contents of image buffer. // 绘制图像缓冲的内容 g.drawImage (imBuffer, 0, 0, this); } void paintChecker (Graphics g, int x, int y) { // Set checker shadow color. // 设置棋子阴影的颜色 g.setColor (Color.black); // Paint checker shadow. // 绘制棋子的阴影 g.fillOval (x, y, CHECKERDIM, CHECKERDIM); // Set checker color. // 设置棋子颜色 g.setColor (Color.red); // Paint checker. // 绘制棋子 g.fillOval (x, y, CHECKERDIM - CHECKERDIM / 13, CHECKERDIM - CHECKERDIM / 13); } void paintCheckerBoard (Graphics g, int x, int y) { // Paint checkerboard outline. // 绘制棋盘轮廓线 g.setColor (Color.black); g.drawRect (x, y, 8 * SQUAREDIM + 1, 8 * SQUAREDIM + 1); // Paint checkerboard. // 绘制棋盘 for (int row = 0; row 8; row++) { g.setColor (((row 1) != 0) ? darkGreen : Color.white); for (int col = 0; col 8; col++) { g.fillRect (x + 1 + col * SQUAREDIM, y + 1 + row * SQUAREDIM, SQUAREDIM, SQUAREDIM); g.setColor ((g.getColor () == darkGreen) ? Color.white : darkGreen); } } } // The AWT invokes the update() method in response to the repaint() method // calls that are made as a checker is dragged. The default implementation // of this method, which is inherited from the Container class, clears the // applet's drawing area to the background color prior to calling paint(). // This clearing followed by drawing causes flicker. CheckerDrag overrides // update() to prevent the background from being cleared, which eliminates // the flicker. // AWT调用了update()方法来响应拖动棋子时所调用的repaint()方法。该方法从 // Container类继承的默认实现会在调用paint()之前，将applet的绘图区域清除 // 为背景色，这种绘制之后的清除就导致了闪烁。CheckerDrag重写了update()来 // 防止背景被清除，从而消除了闪烁。 public void update (Graphics g) { paint (g); }}