java课设迷宫代码,java编写迷宫小游戏

请帮忙用数据结构（java版）的知识解决这道迷宫问题的程序代码。

我这是用c写的。你可以看看，希望能帮助到你。

#include"stdlib.h"

#include"stdio.h"

#define N 50

#define M 50

int X;

int maze[N+2][M+2];

struct point{

int row,col,predecessor;

}queue[512];

int head=0,tail=0;

void shoudong_maze(int m,int n){

int i,j;

printf("\n\n");

printf("请按行输入迷宫，0表示通路，1表示障碍:\n\n");

for(i=0;im;i++)

for(j=0;jn;j++)

scanf("%d",maze[i][j]);

}

void zidong_maze(int m,int n){

int i,j;

printf("\n迷宫生成中……\n\n");

system("pause");

for(i=0;im;i++)

for(j=0;jn;j++)

maze[i][j]=rand()%2;

//由于rand()产生的随机数是从0到RAND_MAX

//RAND_MAX是定义在stdlib.h中的,其值至少为32767)

//要产生从X到Y的数,只需要这样写：k=rand()%(Y-X+1)+X;

}

void print_maze(int m,int n){

int i,j;

printf("\n迷宫生成结果如下:\n\n");

printf("迷宫入口\n");

printf("↓");

for(i=0;im;i++)

{printf("\n");

for(j=0;jn;j++)

{if(maze[i][j]==0) printf("□");

if(maze[i][j]==1) printf("■");}

}

printf("→迷宫出口\n");

}

void result_maze(int m,int n)

{ int i,j;

printf("迷宫通路(用☆表示)如下所示：\n\t");

for(i=0;im;i++)

{ printf("\n");

for(j=0;jn;j++)

{if(maze[i][j]==0||maze[i][j]==2) printf("□");

if(maze[i][j]==1) printf("■");

if(maze[i][j]==3) printf("☆");

}

}

}

void enqueue(struct point p)

{ queue[tail]=p;

tail++;

}

struct point dequeue()

{ head++;

return queue[head-1];

}

int is_empty()

{ return head==tail;

}

void visit(int row,int col,int maze[52][52])

{ struct point visit_point={row,col,head-1};

maze[row][col]=2;

enqueue(visit_point);

}

int mgpath(int maze[52][52],int m,int n)

{ X=1;

struct point p={0,0,-1};

if(maze[p.row][p.col]==1)

{ printf("\n===============================================\n");

printf("此迷宫无解\n\n");X=0;return 0;}

maze[p.row][p.col]=2;

enqueue(p);

while(!is_empty())

{p=dequeue();

if((p.row==m-1)(p.col==n-1)) break;

if((p.col+1n)(maze[p.row][p.col+1]==0)) visit(p.row,p.col+1,maze);

if((p.row+1m)(maze[p.row+1][p.col]==0)) visit(p.row+1,p.col,maze);

if((p.col-1=0)(maze[p.row][p.col-1]==0)) visit(p.row,p.col-1,maze);

if((p.row-1=0)(maze[p.row-1][p.col]==0)) visit(p.row-1,p.col,maze);

}

if(p.row==m-1p.col==n-1)

{printf("\n==================================================================\n");

printf("迷宫路径为：\n");

printf("(%d,%d)\n",p.row,p.col);

maze[p.row][p.col]=3;

while(p.predecessor!=-1)

{p=queue[p.predecessor];

printf("(%d,%d)\n",p.row,p.col);

maze[p.row][p.col]=3;

}

}

else {printf("\n=============================================================\n");

printf("此迷宫无解！\n\n");X=0;}

return 0;

}

int main()

{int i,m,n,cycle=0;

while(cycle!=(-1))

{

printf("********************************************************************************\n");

printf(" ☆欢迎进入迷宫求解系统☆\n");

printf(" 设计者:尹旭 林静波（信息2班）\n");

printf("********************************************************************************\n");

printf(" 手动生成迷宫 请按：1\n");

printf(" 自动生成迷宫 请按：2\n");

printf(" 退出 请按：3\n\n");

printf("********************************************************************************\n");

printf("\n");

printf("请选择你的操作：\n");

scanf("%d",i);

switch(i)

{case 1:printf("\n请输入行数：");

scanf("%d",m);

printf("\n");

printf("请输入列数：");

scanf("%d",n);

while((m=0||m50)||(n=0||n50))

{ printf("\n抱歉，你输入的行列数超出预设范围(0-50,0-50),请重新输入：\n\n");

printf("请输入行数：");

scanf("%d",m);

printf("\n");

printf("请输入列数：");

scanf("%d",n);

}

shoudong_maze(m,n);

print_maze(m,n);

mgpath(maze,m,n);

if(X!=0)

result_maze(m,n);

printf("\n\nPress Enter Contiue!\n");

getchar();

while(getchar()!='\n');

break;

case 2:printf("\n请输入行数：");

scanf("%d",m);

printf("\n");

printf("请输入列数：");

scanf("%d",n);

while((m=0||m50)||(n=0||n50))

{printf("\n抱歉，你输入的行列数超出预设范围(0-50,0-50),请重新输入：\n\n");

printf("请输入行数：");

scanf("%d",m);

printf("\n");

printf("请输入列数：");

scanf("%d",n);

}

zidong_maze(m,n);

print_maze(m,n);

mgpath(maze,m,n);

if(X!=0)

result_maze(m,n);

printf("\n\nPress Enter Contiue!\n");getchar();while(getchar()!='\n');break;

case 3:cycle=(-1);

break;

default:printf("\n");

printf("你的输入有误!\n");

printf("\nPress Enter Contiue!\n");

getchar();

while(getchar()!='\n');break;

}

}

}

相关问答

Q1: 急需一java高手帮忙写一迷宫程序

给你代码，你给出的那两个类，不能满足，我的需要，我就没有使用。

你看一下吧。

----------------------------------------

package stackpackage;

import java.io.BufferedReader;

import java.io.FileReader;

import java.util.ArrayList;

import java.util.List;

import java.util.Scanner;

public class Maze {

// 上

private static Point directionTop = new Point(-1, 0);

// 下

private static Point directionBottom = new Point(1, 0);

// 左

private static Point directionLeft = new Point(0, -1);

// 右

private static Point directionRight = new Point(0, 1);

private static Point[] directions = { directionTop, directionRight,

directionBottom, directionLeft };

private static boolean isStop = false;

private static int row = 0;

private static int col = 0;

private static Point startPoint = new Point();

public static void main(String[] args) throws Exception {

FileReader fr = new FileReader("data.txt");

BufferedReader br = new BufferedReader(fr);

int rowIndex = 1;

int[][] maze = null;

while (br.ready()) {

String line = br.readLine();

Scanner sc = new Scanner(line);

if (rowIndex == 1) {

row = sc.nextInt();

col = sc.nextInt();

maze = new int[row][col];

} else {

if (rowIndex row + 2) {

for (int i = 0; i col; i++) {

maze[rowIndex - 2][i] = sc.nextInt();

}

} else {

startPoint.x = sc.nextInt();

startPoint.y = sc.nextInt();

}

}

rowIndex++;

}

ListPoint route = new ArrayListPoint();

route.add(startPoint);

findNext(startPoint);

puzzle(maze, startPoint, route);

System.out.println(route);

}

private static void puzzle(int[][] maze, Point p, ListPoint route) {

if (isStop) {

return;

}

Point[] nextDirections = p.nextDirections;

for (int i = 0; i nextDirections.length; i++) {

if (isStop) {

return;

}

Point direction = nextDirections[i];

Point newP = new Point(p.x + direction.x, p.y + direction.y);

if (newP.isEffective() maze[newP.x][newP.y] == 0

!route.contains(newP)) {

newP.before = p;

findNext(newP);

route.add(newP);

if (isExit(newP)) {

isStop = true;

break;

}

puzzle(maze, newP, route);

}

}

if (isStop) {

return;

}

route.remove(route.size() - 1);

}

private static void findNext(Point p) {

int index = 0;

Point[] nextDirections = new Point[3];

for (int i = 0; i nextDirections.length; i++) {

nextDirections[i] = new Point(0, 0);

}

for (int i = 0; i directions.length; i++) {

Point direction = directions[i];

Point newP = new Point(p.x + direction.x, p.y + direction.y);

if (newP.isEffective() !newP.equals(p.before) newP.x row

newP.y col) {

nextDirections[index++] = direction;

}

}

p.nextDirections = nextDirections;

}

private static boolean isExit(Point p) {

if (startPoint.equals(p)) {

return false;

}

for (int i = 0; i directions.length; i++) {

Point direction = directions[i];

Point newP = new Point(p.x + direction.x, p.y + direction.y);

if (!newP.equals(p.before)

(newP.x = row || newP.y = col || newP.x 0 || newP.y 0)) {

return true;

}

}

return false;

}

}

class Point {

int x = 0;

int y = 0;

Point[] nextDirections = null;

Point before = null;

public Point() {

}

public Point(int x, int y) {

this.x = x;

this.y = y;

}

public String toString() {

return "" + x + "," + y + "";

}

public boolean isEffective() {

return x = 0 y = 0;

}

public boolean equals(Object obj) {

return equals((Point) obj);

}

public boolean equals(Point p) {

if (p == null) {

return false;

}

return this.x == p.x this.y == p.y;

}

}

Q2: 求走迷宫问题的算法，要求用Java写的？

public class Maze { private int[][] maze = null;

private int[] xx = { 1, 0, -1, 0 };

private int[] yy = { 0, 1, 0, -1 };

private Queue queue = null; public Maze(int[][] maze) {

this.maze = maze;

queue = new Queue(maze.length * maze.length);

} public void go() {

Point outPt = new Point(maze.length - 1, maze[0].length - 1);

Point curPt = new Point(0, 0);

Node curNode = new Node(curPt, null);

maze[curPt.x][curPt.y] = 2;

queue.entryQ(curNode); while (!queue.isEmpty()) {

curNode = queue.outQ();

for (int i = 0; i xx.length; ++i) {

Point nextPt = new Point();

nextPt.x = (curNode.point).x + xx[i];

nextPt.y = (curNode.point).y + yy[i];

if (check(nextPt)) {

Node nextNode = new Node(nextPt, curNode);

queue.entryQ(nextNode);

maze[nextPt.x][nextPt.y] = 2;

if (nextPt.equals(outPt)) {

java.util.StackNode stack = new java.util.StackNode();

stack.push(nextNode);

while ((curNode = nextNode.previous) != null) {

nextNode = curNode;

stack.push(curNode);

}

System.out.println("A Path is:");

while (!stack.isEmpty()) {

curNode = stack.pop();

System.out.println(curNode.point);

}

return;

}

}

}

}

System.out.println("Non solution!");

} private boolean check(Point p) {

if (p.x 0 || p.x = maze.length || p.y 0 || p.y = maze[0].length) {

return false;

}

if (maze[p.x][p.y] != 0) {

return false;

}

return true;

} public static void main(String[] args) {

int[][] maze = {

{ 0, 0, 1, 0, 1, 0, 1, 0, 1, 0 },

{ 0, 0, 1, 1, 1, 0, 0, 0, 1, 0 },

{ 0, 1, 0, 0, 1, 0, 0, 0, 0, 1 },

{ 0, 0, 0, 0, 1, 0, 0, 0, 1, 1 },

{ 0, 0, 1, 0, 0, 0, 0, 0, 0, 1 },

{ 1, 0, 1, 0, 1, 0, 0, 1, 0, 0 },

{ 0, 1, 0, 0, 1, 0, 0, 1, 0, 1 },

{ 1, 0, 1, 0, 1, 1, 0, 1, 0, 0 }

};

new Maze(maze).go();

} private class Queue { Node[] array = null;

int size = 0;

int len = 0;

int head = 0;

int tail = 0; public Queue(int n) {

array = new Node[n + 1];

size = n + 1;

} public boolean entryQ(Node node) {

if (isFull()) {

return false;

}

tail = (tail + 1) % size;

array[tail] = node;

len++;

return true;

} public Node outQ() {

if (isEmpty()) {

return null;

}

head = (head + 1) % size;

len--;

return array[head];

} public boolean isEmpty() {

return (len == 0 || head == tail) ? true : false;

} public boolean isFull() {

return ((tail + 1) % size == head) ? true : false;

}

} private class Node { Point point = null;

Node previous = null; public Node() {

this(null,null);

} public Node(Point point, Node node) {

this.point = point;

this.previous = node;

}

} private class Point { int x = 0;

int y = 0; public Point() {

this(0, 0);

} public Point(int x, int y) {

this.x = x;

this.y = y;

} public boolean equals(Point p) {

return (x == p.x) (y == p.y);

} @Override

public String toString() {

return "(" + x + "," + y + ")";

}

}

}

Q3: java老鼠迷宫代码难吗

非常难。思路：

1、设老鼠的行进路线都是优先选择下-右-上-左。

2、设老鼠很聪明，走过的路线走撒泡尿，表示鼠大爷到此一游，我们可以把数组的值改为3，表示走过，但走不通。

3、这是一个int[8][8]的二位数组，那么开始位置下标是1,1，结束位置是6,6。行和列分别用、j表示。

4、实际路线我们可以设置2表示，我们可以使用递归，让老鼠不断测试路线。

5、最后打印数组，看老鼠的实际路线。

Q4: Java迷宫的游戏

这个太简单了。。我用类C的代码写给你看看。。。直接手写的，不调试了

，谁让你就给这点分呢。。。。其实分啥都不是。。。

其实就是搜索，为了简单我就用深度优先了

int dir[4][2]={

{1,0},

{-1,0},

{0,1},

{0,-1}

};//用来控制方向的数组

int flag = 0;

int map[][];//这个就是你的迷宫

void dfs( int x, int y ){

if( flag ){

return;

}

map[x][y] = 0;

for(int i = 0; i 4; i++ ){

int dx = x + dir[i][0];

int dy = y + dir[i][1];

if( 0 = dx dx 行数 0 = dy dy 列数 map[dx][dy] == 1 ){

dfs(dx,dy);

}

}

map[x][y] = 1;

}

这个就是回溯函数了。。。。