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Java---Ajax在Struts2框架的应用实例
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Ajax 是一种在无需重新加载整个网页的情况下，能够更新部分网页的技术。
很久没有动过ajax了,趁此机会复习一下,写一个简单的例子
一.项目结构:
二.需要的jar包
三.具体代码:
1.web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>Struts2</display-name>
<filter>
<filter-name>struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
2.Action
UserLoginAction.java
package Action; import com.opensymphony.xwork2.ActionSupport; /**
* @author user:liuadmin
* @version date：2017年12月8日 上午6:54:00
*
*/ public class UserLoginAction extends ActionSupport { private static final long serialVersionUID = 1L;
private String username;
private String password; public String getUsername() {
return username;
} public void setUsername(String username) {
this.username = username;
} public String getPassword() {
return password;
} public void setPassword(String password) {
this.password = password;
} /**
* userlogin
*
* @return SUCCESS
*/
public String login() {
System.out.println("execute!!!");
if ("admin".equals(this.username) && "123".equals(this.password))
return "success";
else if (password == null && username == null)
return "error";
else
return "error";
} }
AjaxAction.java
package Action; import java.util.HashMap;
import java.util.Map; import javax.servlet.http.HttpServletRequest; import net.sf.json.JSONObject; import org.apache.struts2.interceptor.ServletRequestAware; import com.opensymphony.xwork2.ActionSupport; /**
* @author user:liuadmin
* @version date：2017年12月8日 上午6:56:00
*
*/ public class AjaxAction extends ActionSupport implements ServletRequestAware {
private static final long serialVersionUID = 1L; private HttpServletRequest request;
private String result; public void setServletRequest(HttpServletRequest arg0) {
this.request = arg0;
} public String getResult() {
return result;
} public void setResult(String result) {
this.result = result;
} /**
* 处理ajax请求
*
* @return SUCCESS
*/
public String executeAjax() {
try {
// 获取数据
String name = request.getParameter("name");
int age = Integer.parseInt(request.getParameter("age"));
String position = request.getParameter("position"); // 将数据存储在map里，再转换成json类型数据，也可以自己手动构造json类型数据
Map<String, Object> map = new HashMap<String, Object>();
map.put("name", name);
map.put("age", age);
map.put("position", position); JSONObject json = JSONObject.fromObject(map);// 将map对象转换成json类型数据
result = json.toString();// 给result赋值，传递给页面
} catch (Exception e) {
e.printStackTrace();
}
return SUCCESS;
} }
3.struts.xml
<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.3//EN"
"http://struts.apache.org/dtds/struts-2.3.dtd">
<struts>
<!--解决乱码 -->
<constant name="struts.i18n.encoding" value="UTF-8"></constant> <include file="struts-default.xml" /> <package name="struts" extends="struts-default,json-default"> <action name="login" class="Action.UserLoginAction" method="login"> <result name="success">/success.jsp</result>
<result name="error">/error.jsp</result> </action> <action name="executeAjax" method="executeAjax" class="Action.AjaxAction">
<result name="fail"></result>
<!-- 返回json类型数据 -->
<result type="json">
<param name="root">result<!-- result是action中设置的变量名，也是页面需要返回的数据，该变量必须有setter和getter方法 --></param>
</result>
</action> </package>
</struts>
4.jsp
index.jsp
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01
Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Login</title>
</head>
<body> Please enter your account number and password
<form id="from" action="login" method="post">
account number：<input type="text" name="username" id="username" /><br />
password：<input type="password" name="password" id="pass" /><br /> <input
type="submit" value="login" />
</form> </body>
</html>
success.jsp
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Ajax+Struts2 is Demo</title>
</head>
<body >
====>Login successfully！<br />
account number：${request.username}<br />
password：${request.password}<br>
<div id="div_json">
<h5>录入数据</h5>
<br />
<form action="executeAjax" method="post">
<label for="name">姓名：</label><input type="text" name="name" />
<label for="age">年龄：</label><input type="text" name="age" />
<label for="position">职务：</label><input type="text" name="position" />
<input type="button" class="btn" value="提交结果"/>
</form>
<br />
<h5>显示结果</h5>
<br />
<ul>
<li>姓名：<span id="s_name">赞无数据</span></li>
<li class="li_layout">年龄：<span id="s_age">暂无数据</span></li>
<li class="li_layout">职务：<span id="s_position">暂无数据</span></li>
</ul>
</div> <script type="text/javascript" src="js/jquery-1.8.2.js"></script>
<script type="text/javascript"> /* 提交结果，执行ajax */
function btn(){ var $btn = $("input.btn");//获取按钮元素
//给按钮绑定点击事件
$btn.bind("click",function(){ $.ajax({
type:"post",
url:"AjaxAction/executeAjax",//需要用来处理ajax请求的action,excuteAjax为处理的方法名，JsonAction为action名
data:{//设置数据源
name:$("input[name=name]").val(),
age:$("input[name=age]").val(),
position:$("input[name=position]").val()//这里不要加"," 不然会报错，而且根本不会提示错误地方
},
dataType:"json",//设置需要返回的数据类型
success:function(data){
var d = eval("("+data+")");//将数据转换成json类型，可以把data用alert()输出出来看看到底是什么样的结构
//得到的d是一个形如{"key":"value","key1":"value1"}的数据类型，然后取值出来 $("#s_name").text(""+d.name+"");
$("#s_age").text(""+d.age+"");
$("#s_position").text(""+d.position+""); },
error:function(){
alert("系统异常，请稍后重试！");
}//这里不要加","
});
});
} /* 页面加载完成，绑定事件 */
$(document).ready(function(){
btn();//点击提交，执行ajax
});
</script>
</body>
</html>
error.jsp
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>error</title>
</head>
<body>
Login failed
</body>
</html>
代码上重要的地方都会注释,不明白的可以评论.
源码下载: https://pan.baidu.com/s/1jIAarKM 密码: exgk
