java中计算一段时间内白天的时间和夜晚的时间

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之前，采用拼接字符串的形式，不断地在Date类型和Long类型之间转换，实在是太过于麻烦，后来采取了这种思路：假设我们将22:00 ~ 10:00 视为夜间时间，则我们先计算出10:00 相对于当天的分钟数，22:00 相对于当天的分钟数，然后将我们取到的Date转换成Long型，加上8 * 60 * 60 * 1000，对一天的分钟数取余，根据结果来判断是在白天还是夜晚，while循环中继续累加下一分钟，下面见具体算法

package com.company;

import com.sun.scenario.Settings;

import java.io.File;
import java.io.IOException;
import java.net.URL;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.time.LocalDateTime;
import java.time.format.DateTimeFormatter;
import java.util.Date;
import java.util.regex.Pattern;

public class Main {

    public static void main(String[] args) throws ParseException {

        SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
        Date startOrderTime = sdf.parse("2018-05-23 14:00:00");
        Date endOrderTime = sdf.parse("2018-05-24 14:36:28");
        String staN = "22:00:00";
        String etaN = "10:00:00";
        new Main().calcRoughly(startOrderTime, endOrderTime, staN, etaN);
    }

    private void calcRoughly(Date startOrderTime, Date endOrderTime, String startTimeAtNight, String endTimeAtNight) {
        // 以分钟为单位进行统计
        long dayTime = 0;
        long nightTime = 0;
        long startTime = startOrderTime.getTime();
        long endTime = endOrderTime.getTime();
        long startCurMinutes = calcCurMinutes(startTimeAtNight);
        long endCurMinutes = calcCurMinutes(endTimeAtNight);
        while (startTime <= endTime) {
            long modTime = ((startTime + 8 * 60 * 60 * 1000) / (1000 * 60)) % (24 * 60);
            if (modTime >= endCurMinutes && modTime < startCurMinutes) {
                dayTime += 1;
            }
            else {
                nightTime += 1;
            }
            startTime += (1000 * 60);
        }
        System.out.println(dayTime);
        System.out.println(nightTime);
    }

    // 时间字符串 "22:00:00"
    long calcCurMinutes(String time) {
        String pattern = "\\d{2}:\\d{2}:\\d{2}";
        if (Pattern.matches(pattern, time)) {
            int hour = Integer.valueOf(time.substring(0, 2));
            int minutes = Integer.valueOf(time.substring(3, 5));
            return hour * 60 + minutes;
        }
        return 0;
    }

}