
正文
leetcode-easy-listnode-237 Delete Node in a Linked List
提示:扫一扫查出行【扫一扫了解最新限行尾号】
复制提示
mycode
# Definition for singly-linked list.
# class ListNode(object):
# def __init__(self, x):
# self.val = x
# self.next = None class Solution(object):
def deleteNode(self, node):
"""
:type node: ListNode
:rtype: void Do not return anything, modify node in-place instead.
"""
node.val = node.next.val
node.next = node.next.next






