蜗牛慢慢爬 LeetCode 7. Reverse Integer [Difficulty: Easy]

题目

Reverse digits of an integer.

Example1: x = 123, return 321

Example2: x = -123, return -321

Have you thought about this?

Here are some good questions to ask before coding. Bonus points for you if you have already thought through this!

If the integer's last digit is 0, what should the output be? ie, cases such as 10, 100.

Did you notice that the reversed integer might overflow? Assume the input is a 32-bit integer, then the reverse of 1000000003 overflows. How should you handle such cases?

For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.

Note:

The input is assumed to be a 32-bit signed integer. Your function should return 0 when the reversed integer overflows.

翻译

很简单的整数倒置 需要注意的是符号和范围

利用Python则很简单

Hints

Related Topics: Math

代码

Java

class Solution {
public int reverse(int x) {
long result = 0;
while(x!=0){
result = result*10+x%10;
if(result>Integer.MAX_VALUE||result<Integer.MIN_VALUE)
return 0;
x = x/10;
}
return (int)result;
}
}


Python

class Solution(object):
def reverse(self, x):
sign = 1 if x>=0 else -1
x = x*sign
xs = str(x)
ys = xs[::-1] y = int(ys)*sign
if y>2**31-1 or y<-2**31:
return 0
return y