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c语言分段函数y=1x,C语言分段函数计算
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c语言编程题：求分段函数的值 y=1+e的x平方 x>0；y=1 x=0；y=ln2平方 x
static void Main(string[] args)
{
while (true)
{
Console.Write("请输入x的值：\nx=");
double x = double.Parse(Console.ReadLine());
double y;
const double e = 2.71828;
if (x 0)
{
y = Math.Log(e, 2);
}
else if (x == 0)
{
y = 1;
}
else
{
y = 1 + Math.Exp(x);
}
Console.WriteLine("y="+y);
}
}
相关问答
Q1: C语言题：用4种if else结构把分段函数y=x，x＞0 y=1,x＜0 y＝-1,x＝0 y＝
void main()
{
int x,y=0;
printf("请输入一个整数\n");
scanf("%d", x);
printf("x=%d\n", x);
if(x0){
y =1;
}else if(x0){
y=-1;
}else if(x=0){
y=0;
}else {
printf("您的输入有误");
}
printf("y=%d\n", y);
}
// 希望可以帮到你望采纳~
Q2: C语言分段函数y=-1(x>9) ;y=x*(x+2)(3
#include stdio.h
int main()
{
int x,y;
scanf("%d",x);
if(x9)
y=-1;
else if(3x x=9)
y=x*(x+2);
else if(-1x x=3)
y=2*x;
else if(x=-1)
y=x-1;
printf("%d\n",y);
while(1);
return 0;
}
不能连续比较
Q3: C语言计算分段函数
1. 代码如下，3）需要实际运行时输入测试
int main(void)
{
double x, y, f;
printf("Please input 2 double number in the form of x y:\n");
scanf("%lf%lf", x, y);
if(x=0 y0)
f = 2*x*x + 3*x +1/(x+y);
else if(x=0 y=0)
f = 2*x*x + 3*x +1/(1+y*y);
else
f = 3*sin(x+y)/(2*x*x) + 3*x + 1;
printf("x=%lf, y=%lf, f(x, y)=%lf\n", x, y, f);
return 0;
}
2.代码如下
#include stdio.h
#includemath.h
int main(void)
{
double x, y, f;
printf("Please input 2 double number in the form of x y:\n");
scanf("%lf%lf", x, y);
if(x=0)
{
if(y0)
f = 2*x*x + 3*x +1/(x+y);
else
f = 2*x*x + 3*x +1/(1+y*y);
}
else
f = 3*sin(x+y)/(2*x*x) + 3*x + 1;
printf("x=%lf, y=%lf, f(x, y)=%lf\n", x, y, f);
return 0;
}
3.代码如下
#include stdio.h
int main(void)
{
int score = 0;
printf("Please input a score between 0-100:\n");
scanf("%d", score);
if(score0 || score100)
printf("Wrong input of score!\n");
else if(score=90 score=100)
printf("A\n");
else if(score=80 score=89)
printf("B\n");
else if(score=70 score=79)
printf("C\n");
else if(score=60 score=69)
printf("D\n");
else
printf("E\n");
return 0;
}
