c++实现扫雷（坐标）

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昨天在观察贪食蛇的代码时，看到了有如何实现扫雷的c++代码，觉得挺有趣，今天便又试了一下

#include <ctime>

#include <cstdlib>

#include <iostream>

using namespace std;

int map[][];    // 为避免边界的特殊处理，故将二维数组四周边界扩展1

int derection[] = { , , - };  //方向数组

int calculate ( int x, int y )

{

 int counter = ;

 for ( int i = ; i < ; i++ )

  for ( int j = ; j < ; j++ )

   if ( map[ x+derection[i]][ y+derection[j] ] ==  )

    counter++;                 // 统计以(x,y)为中心的四周的雷数目

 return counter;

}

void game ( int x, int y )

{

    if ( calculate ( x, y ) ==  )

 {

  map[x][y] = ;

  for ( int i = ; i < ; i++ )

  {                                  // 模拟游戏过程，若点到一个空白，则系统自动向外扩展

   for ( int j = ; j < ; j++ )

    if ( x+derection[i] <=  && y+derection[j] <=  && x+derection[i] >=  && y+derection[j] >=

     && !( derection[i] ==  && derection[j] ==  ) &&  map[x+derection[i]][y+derection[j]] == - )

                      game( x+derection[i], y+derection[j] ); // 条件比较多，一是不可以让两个方向坐标同时为0，否则

  }                                                      //二是递归不能出界.三是要保证不返回调用。

 }

 else

  map[x][y] = calculate(x,y);

}

void print ()

{

 for ( int i = ; i < ; i++ )

 {

  for ( int j = ; j < ; j++ )

  {

   if ( map[i][j] == - || map[i][j] ==  )

    cout << "#";

   else

    cout << map[i][j];

  }

  cout << endl;

 }

}

bool check ()

{

 int counter = ;

 for ( int i = ; i < ; i++ )

  for ( int j = ; j < ; j++ )

   if ( map[i][j] != - )

    counter++;

 if ( counter ==  )

  return true;

 else

  return false;

}

int main ()

{

 int i, j, x, y;

 char ch;

 srand ( time (  ) );

 do

 {

  memset ( map, -, sizeof(map) );  // 将map全部初始化为-1，以后用-1表示未涉及的区域

  for ( i = ; i < ;  )

  {

   x = rand()% + ;

   y = rand()% + ;

   if ( map[x][y] !=  )

   {

    map[x][y] = ;

    i++;

   }

  }

  for ( i = ; i < ; i++ )

  {

   for ( j = ; j < ; j++ )

    cout << "#";

   cout << "\n";

  }

  cout << "\n";

  cout << "Please enter a coordinate: ";

  while ( cin >> x >> y )

  {

   if ( map[x][y] ==  )

   {

    cout << "GAME OVER" << endl;    //点中雷之后游戏结束，并且输出雷的位置

    for ( i = ; i < ; i++ )

    {

     for ( j = ; j < ; j++ )

     {

      if ( map[i][j] ==  )

       cout << "@";

      else

       cout << "#";

     }

     cout << endl;

    }

    break;

   }

   game(x,y);

   print();

   if ( check () )

   {

    cout << "YOU WIN" << endl;

    break;

   }

   cout << "\n\n";

  }

  cout << "Do you want to play again, if true enter Y, or enter N" << endl;

  cin >> ch;

  cout << "\n\n";

 } while ( ch == 'Y' );

 return ;

}