
正文
C# 根据年月获得此月第一天和最后一天,并计算工作日
提示:扫一扫查出行【扫一扫了解最新限行尾号】
复制提示
string str = "2015年3月";
int firstIndex = str.IndexOf("年", );
int secondIndex = str.IndexOf("月", firstIndex + );
string month = str.Substring(firstIndex + , secondIndex - firstIndex - );
string year = str.Substring(, );
DateTime dt = DateTime.Now;
string[] time = dt.ToString().Split(new char[]{'/'});
string date = year + "/" + month + "/" + time[];
DateTime first = Convert.ToDateTime(date).AddDays( - Convert.ToDateTime(date).Day);
DateTime last=Convert.ToDateTime(date).AddDays( - Convert.ToDateTime(date).Day).AddMonths().AddDays(-);
//The first day of the month
Label1.Text = first.ToString();
//The last day of the month
Label2.Text = last.ToString();
//businessDays of the month(except on the weekend)
Label3.Text = getint(first, last).ToString();
getint 方法:
public int getint(DateTime firstDay, DateTime lastDay)
{
firstDay = firstDay.Date;
lastDay = lastDay.Date;
if (firstDay > lastDay)
throw new ArgumentException("Incorrect last day " + lastDay);
TimeSpan span = lastDay - firstDay;
int businessDays = span.Days + ;
int fullWeekCount = businessDays / ;
// find out if there are weekends during the time exceedng the full weeks
if (businessDays > fullWeekCount * )
{
// we are here to find out if there is a 1-day or 2-days weekend
// in the time interval remaining after subtracting the complete weeks
int firstDayOfWeek = firstDay.DayOfWeek == DayOfWeek.Sunday ? : (int)firstDay.DayOfWeek;
int lastDayOfWeek = lastDay.DayOfWeek == DayOfWeek.Sunday ? : (int)lastDay.DayOfWeek; if (lastDayOfWeek < firstDayOfWeek)
lastDayOfWeek += ;
if (firstDayOfWeek <= )
{
if (lastDayOfWeek >= )// Both Saturday and Sunday are in the remaining time interval
businessDays -= ;
else if (lastDayOfWeek >= )// Only Saturday is in the remaining time interval
businessDays -= ;
}
else if (firstDayOfWeek <= && lastDayOfWeek >= )// Only Sunday is in the remaining time interval
businessDays -= ;
}
// subtract the weekends during the full weeks in the interval
businessDays -= fullWeekCount + fullWeekCount;
return businessDays;
}








