Android忘记密码功能实现

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连续好几天学习都没有什么进展，然而在今天这个烂漫的日子。突然有了学习的动力。想起来前几日老师给布置的android忘记密码的功能实现。今天也有了想法。就是按照老师的建议，简单的回答一个问题，实现此功能。我就模仿之前写的登录的例子。实现了此功能。我的想法是：回答之前绑定的手机号。如果正确则忘记密码成功。反之失败。

现在开始上效果图片：

android端的代码：

ForgetActivity.java

package com.itcast.forget;import java.io.InputStream;
import java.net.HttpURLConnection;
import java.net.URL;import android.os.Bundle;
import android.os.Handler;
import android.os.Message;
import android.app.Activity;
import android.content.Intent;
import android.text.TextUtils;
import android.view.Menu;
import android.view.View;
import android.widget.EditText;
import android.widget.Toast;public class ForgetActivity extends Activity {
private EditText et_phone;
protected static final int ERROR = 2;
protected static final int SUCCESS = 1;
private Handler handler = new Handler(){
public void handleMessage(Message msg) {
switch (msg.what) {
case SUCCESS:
Toast.makeText(ForgetActivity.this,(String)msg.obj, 1).show(); break; case ERROR:
Toast.makeText(ForgetActivity.this,"失败", 1).show();
break; }
};
}; @Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_forget);
et_phone = (EditText) findViewById(R.id.et_phone);
} public void btn_ok(View view){
final String phone = et_phone.getText().toString().trim();
if (TextUtils.isEmpty(phone)) {
Toast.makeText(this, "手机号不能为空！", 0).show();
return;
}
new Thread(){
public void run(){
try{
String path = "http://192.168.1.105:80/xampp/forget.php";
URL url = new URL(path);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("POST");
conn.setRequestProperty("User-Agent", "Mozilla/5.0(compatible;MSIE 9.0;Windows NT 6.1;Trident/5.0)");
conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");//请求的类型表单数据
String data = "phone="+phone+"&button=";
conn.setRequestProperty("Content-Length", data.length()+"");//数据的长度
conn.setDoOutput(true);//设置向服务器写数据
byte[] bytes = data.getBytes();
conn.getOutputStream().write(bytes);//把数据以流的方式写给服务
int code = conn.getResponseCode();
if(code == 200){
InputStream is = conn.getInputStream();
String result = StreamTools.readStream(is);
Message mas= Message.obtain();
mas.what = SUCCESS;
mas.obj = result;
handler.sendMessage(mas); }else{
Message mas = Message.obtain();
mas.what = ERROR;
handler.sendMessage(mas);
} }catch(Exception e){
Message mas = Message.obtain();
mas.what = ERROR;
handler.sendMessage(mas);
}
};
}.start();
}}

MainActivity.java

package com.itcast.forget;import android.os.Bundle;
import android.app.Activity;
import android.content.Intent;
import android.view.Menu;
import android.view.View;
import android.widget.Button;public class MainActivity extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
} public void forget(View view){
Intent intent = new Intent(this,ForgetActivity.class);
startActivity(intent);
}}

StreamTools.java

package com.itcast.forget;import java.io.ByteArrayOutputStream;
import java.io.IOException;
import java.io.InputStream;public class StreamTools { public static String readStream(InputStream is){
try {
ByteArrayOutputStream baos = new ByteArrayOutputStream();
byte[] buffer = new byte[1024];
int len = -1;
while ((len = is.read(buffer))!=-1) {
baos.write(buffer,0,len);
}
baos.close();
return new String(baos.toByteArray());
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
return "";
}
}
}

activity_forget.xml

activity_main.xml

添加权限：<uses-permission android:name="android.permission.INTERNET"/>

PHP代码：

<?php
if(isset($_POST['button'])){
$phone=$_POST['phone'];//得到用户输入的手机号
if($phone == "123456"){//假设用户的手机号为123456
echo '哈哈。。。成功忘记密码';
}else{
echo '操作失败！';
}
}else{
echo 'test!';
}
?>