
正文
selenium-显式等待与隐式等待(3)
提示:扫一扫查出行【扫一扫了解最新限行尾号】
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示例代码:
from selenium.webdriver.support.wait import WebDriverWait as WD
def find_element(self, by, locator):
"""
find alone element
:param by: eg: id, name, xpath, css.....
:param locator: id, name, xpath for str
:return: element object
"""
try:
print('[Info:Starting find the element "{}" by "{}"!]'.format(locator, by))
element = WD(self.driver, self.outTime).until(lambda x: x.find_element(by, locator)) # 其实指driver
except TimeoutException as t:
print('error: found "{}" timeout!'.format(locator), t)
else:
return element
对于 element = WD(self.driver, self.outTime).until(lambda x: x.find_element(by, locator))如何理解?
它是说程序每隔xx秒看一眼,如果条件成立了,则执行下一步;否则继续等待,直到超过设置的最长时间,然后抛出TimeoutException异常
def until(self, method, message=''):
"""Calls the method provided with the driver as an argument until the \
return value is not False."""
screen = None
stacktrace = None end_time = time.time() + self._timeout
while True:
try:
value = method(self._driver)
if value:
return value
except self._ignored_exceptions as exc:
screen = getattr(exc, 'screen', None)
stacktrace = getattr(exc, 'stacktrace', None)
time.sleep(self._poll)
if time.time() > end_time:
break
raise TimeoutException(message, screen, stacktrace)







