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计算 Python (list or array) 相同索引元素相等的个数

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12/01
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上代码： 

a = [2, 3, 3, 1, 1, 3, 3, 3, 2, 1, 3, 1, 3, 2, 2, 2, 3, 1, 2, 3, 2, 3,

       1, 1, 2, 1, 1, 1, 2, 2, 3, 3, 2, 3, 1, 1, 3, 1, 2, 1, 2, 3, 3, 3,

       2, 2, 3, 1, 2, 3, 1, 1, 2, 3, 2, 1, 2, 2, 2, 1, 1, 2, 2, 2, 3, 3,

       2, 3, 2, 2, 3, 1, 1, 2, 1, 1, 1, 1, 1, 3, 2, 2, 2, 2, 2, 3, 3, 1,

       3, 3, 3, 1, 2, 1, 3, 1, 2, 1, 3, 1]

b = [2, 1, 1, 1, 1, 3, 3, 3, 2, 1, 3, 3, 3, 2, 2, 2, 3, 1, 2, 3, 2, 3,

       1, 3, 2, 1, 1, 1, 2, 3, 3, 1, 2, 3, 1, 1, 1, 3, 2, 1, 2, 3, 3, 3,

       2, 2, 3, 3, 2, 3, 1, 3, 2, 3, 2, 1, 2, 2, 2, 3, 1, 2, 2, 2, 3, 3,

       2, 3, 2, 2, 3, 1, 1, 2, 1, 3, 1, 1, 3, 3, 2, 2, 2, 2, 2, 3, 3, 3,

       3, 3, 3, 3, 2, 1, 3, 1, 2, 1, 3, 3]

import numpy as np

a = np.array(a)

b = np.array(b)

sum(a==b) #个数为84

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