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python实现两个经纬度点之间的距离和方位角
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from：http://blog.csdn.net/zhuqiuhui/article/details/53180395
1. 求两个经纬点的方位角，P0(latA, lonA), P1(latB, lonB)（很多博客写的不是很好，这里总结一下）
def getDegree(latA, lonA, latB, lonB):
"""
Args:
point p1(latA, lonA)
point p2(latB, lonB)
Returns:
bearing between the two GPS points,
default: the basis of heading direction is north
"""
radLatA = radians(latA)
radLonA = radians(lonA)
radLatB = radians(latB)
radLonB = radians(lonB)
dLon = radLonB - radLonA
y = sin(dLon) * cos(radLatB)
x = cos(radLatA) * sin(radLatB) - sin(radLatA) * cos(radLatB) * cos(dLon)
brng = degrees(atan2(y, x))
brng = (brng + 360) % 360
return brng
2. 求两个经纬点的距离函数：P0(latA, lonA), P1(latB, lonB)
def haversine(a, b): # 经度1，纬度1，经度2，纬度2 （十进制度数）
"""
Calculate the great circle distance between two points
on the earth (specified in decimal degrees)
"""
lat1 = a[0][0]
lon1 = a[1][0]
lat2 = b[0][0]
lon2 = b[1][0] # 将十进制度数转化为弧度
lon1, lat1, lon2, lat2 = map(radians, [lon1, lat1, lon2, lat2]) # haversine公式
dlon = lon2 - lon1
dlat = lat2 - lat1
a = sin(dlat/2)**2 + cos(lat1) * cos(lat2) * sin(dlon/2)**2
c = 2 * asin(sqrt(a))
r = 6371 # 地球平均半径，单位为公里
return c * r * 1000
