[算法导论]二叉查找树的实现 @ Python

class Tree:
def __init__(self):
self.root = None# Definition for a binary tree node
class TreeNode:
def __init__(self, x):
self.val = x
self.left = None
self.right = None
self.parent = Noneclass Solution:
# @param root, a tree node
# @return an integer
def TreeSearch(self, x, k):
if x == None or x.val == k:
return x
if k < x.val:
return self.TreeSearch(x.left, k)
else:
return self.TreeSearch(x.right, k) def IterativeTreeSearch(self, x, k):
while x != None and x.val != k:
if k < x.val:
x = x.left
else:
x = x.right
return x def TreeMinimum(self, x):
while x.left != None:
x = x.left
return x def TreeMaximum(self, x):
while x.right != None:
x = x.right
return x def TreeSuccessor(self, x):
if x.right != None:
return self.TreeMinimum(x)
y = x.parent
while y != None and x == y.right:
x = y
y = y.parent
return y def TreeInsert(self, T, z):
y = None
x = T.root
while x != None:
y = x
if z.val < x.val:
x = x.left
else:
x = x.right
z.parent = y
if y == None:
T.root = z
elif z.val < y.val:
y.left = z
else:
y.right = z def InorderTreeWalk(self, x):
if x != None:
self.InorderTreeWalk(x.left)
print x.val
self.InorderTreeWalk(x.right) def Transplant(self, T, u, v):
if u.parent == None:
T.root = v
elif u == u.parent.left:
u.parent.left = v
else:
u.parent.right = v
if v != None:
v.parent = u.parent def TreeDelete(self, T, z):
if z.left == None:
self.Transplant(T, z, z.right)
elif z.right == None:
self.Transplant(T, z, z.left)
else:
y = self.TreeMinimum(z.right)
if y.parent != z:
self.Transplant(T,y,y.right)
y.right = z.right
y.right.parent = y
self.Transplant(T, z, y)
y.left = z.left
y.left.p = y# root = TreeNode(15)
T = Tree()
nodes = [6,18,3,7,17,20,2,4,13,9]
s = Solution()
for node in nodes:
s.TreeInsert(T,TreeNode(node))
s.InorderTreeWalk(T.root)
s.TreeDelete(T, T.root)
s.InorderTreeWalk(T.root)