PAT-B 1015. 德才论(同PAT 1062. Talent and Virtue)

1. 在排序的过程中，注意边界的处理（小于、小于等于）

2. 对于B-level，这题是比較麻烦一些了。

源代码：

#include <cstdio>

#include <vector>

#include <algorithm>

using namespace std;

struct People

{

	int m_id;

	int m_virtue;

	int m_talent;

	People(int id, int virtue, int talent): m_id(id), m_virtue(virtue), m_talent(talent) {}

	void print()

	{

		printf("%08d %d %d\n", m_id, m_virtue, m_talent);

	}

	friend bool operator< (const People& a, const People& b)

	{

		if (a.m_virtue+a.m_talent != b.m_virtue+b.m_talent)

		{

			return a.m_virtue+a.m_talent > b.m_virtue+b.m_talent;

		} else if (a.m_virtue != b.m_virtue)

		{

			return a.m_virtue > b.m_virtue;

		} else

		{

			return a.m_id < b.m_id;

		}

	}

};

vector<People> sage, noble_man, fool_man, small_man;

int n, l, h;

int id, virtue, talent;

int main()

{

	scanf("%d%d%d", &n, &l, &h);

	for (int i = 0; i < n; ++ i)

	{

		scanf("%d%d%d", &id, &virtue, &talent);

		if (virtue < l || talent < l)

		{

			continue;

		} else if (virtue >= h && talent >= h)

		{

			sage.push_back( People(id, virtue, talent) );

		} else if (virtue  >= h)

		{

			noble_man.push_back( People(id, virtue, talent) );

		} else if (virtue >= talent)

		{

			fool_man.push_back( People(id, virtue, talent) );

		} else

		{

			small_man.push_back( People(id, virtue, talent) );

		}

	}

	sort(sage.begin(), sage.end());

	sort(noble_man.begin(), noble_man.end());

	sort(fool_man.begin(), fool_man.end());

	sort(small_man.begin(), small_man.end());

	printf("%d\n", sage.size() + noble_man.size() + fool_man.size() + small_man.size());

	for (size_t i = 0; i < sage.size(); ++ i)

	{

		sage[i].print();

	}

	for (size_t i = 0; i < noble_man.size(); ++ i)

	{

		noble_man[i].print();

	}

	for (size_t i = 0; i < fool_man.size(); ++ i)

	{

		fool_man[i].print();

	}

	for (size_t i = 0; i < small_man.size(); ++ i)

	{

		small_man[i].print();

	}

	return 0;

}