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JavaScript校验输入的字符串是否包含特殊字符
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校验在文本框输入的字符串中是否包含特殊字符串,js代码如下
function strInclude(substring){
if(substring){
var reg = new RegExp("[~#^$@%&!?%*]", 'g');
if (substring.match(reg)) {
return true;
}
for ( var i = ; i < substring.length; i++) {
var hs = substring.charCodeAt(i);
if (0xd800 <= hs && hs <= 0xdbff) {
if (substring.length > ) {
var ls = substring.charCodeAt(i + );
var uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;
if (0x1d000 <= uc && uc <= 0x1f77f) {
return true;
}
}
} else if (substring.length > ) {
var ls = substring.charCodeAt(i + );
if (ls == 0x20e3) {
return true;
}
} else {
if (0x2100 <= hs && hs <= 0x27ff) {
return true;
} else if (0x2B05 <= hs && hs <= 0x2b07) {
return true;
} else if (0x2934 <= hs && hs <= 0x2935) {
return true;
} else if (0x3297 <= hs && hs <= 0x3299) {
return true;
} else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030
|| hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b
|| hs == 0x2b50) {
return true;
}
}
}
}
}







