[Solution] 简单数字识别之Tesseract

private static void Reverse(string fileName,string outName)
{
using (var pic = Image.FromFile(fileName) as Bitmap)
{
for (int i = ; i < pic.Width; i++)
{
for (int j = ; j < pic.Height; j++)
{
var c = pic.GetPixel(i, j);
c = Color.FromArgb( - c.R, - c.G, - c.B);
pic.SetPixel(i, j, c);
}
}
pic.Save(outName);
}
}

private Image Analyse(string fileName)//为方便,方法参数没有用Image
{
using (var map = Image.FromFile(fileName) as Bitmap)
{
if (map == null) return null;
Point p1;
Point p2;
var p = GetConfig(out p1, out p2);
var pic = new Bitmap(p.X, p.Y);
var x = ;
var y = ;
for (int i = ; i < map.Height; i++)
{
if (i >= p1.Y && i <= p2.Y)
{
for (int j = ; j < map.Width; j++)
{
if (j >= p1.X && j <= p2.X)
{
pic.SetPixel(x, y, map.GetPixel(j, i));
x++;
}
}
x = ;
y++;
}
}
return pic;
}
} private Point GetConfig(out Point p1, out Point p2)
{
var p1Str = ConfigurationManager.AppSettings["p1"].Split(',');
var p2Str = ConfigurationManager.AppSettings["p2"].Split(',');
p1 = new Point() { X = int.Parse(p1Str[]), Y = int.Parse(p1Str[]) };
p2 = new Point() { X = int.Parse(p2Str[]), Y = int.Parse(p2Str[]) };
return new Point() { X = p2.X - p1.X + , Y = p2.Y - p1.Y + };
} class Point
{
/// <summary>
/// 点的X坐标,或者宽度
/// </summary>
public int X { get; set; }
/// <summary>
/// 点的Y坐标,或者高度
/// </summary>
public int Y { get; set; }
}