javascript 简单实现对两个数组相似度的检验

提示：扫一扫查出行
【扫一扫了解最新限行尾号】
复制提示

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html;charset=UTF-8">
<title>js 检测两个数组是否相似</title>
</head>
<body>
<script>
//数组中的成员类型相同，顺序可以不同。例如[1, true] 与 [false, 2]是相似的。
//数组的长度一致。
//类型的判断范围，需要区分:String, Boolean, Number, undefined, null, 函数，日期, window.
function arraysSimilar(arr1, arr2){
//判断边界
if (!(arr1 instanceof Array) || !(arr2 instanceof Array)) {
return false;
} //判断长度
if (arr1.length != arr2.length) return false; var i = 0, n = arr1.length, countMap1 = {}, countMap2 = {}, t1, t2, TYPES = ['string', 'boolean', 'number', 'undefined', null, 'function', 'date', 'window']; for ( ; i < n; i++) {
t1 = typeOf(arr1[i]);
t2 = typeOf(arr2[i]);
if (countMap1[t1]) {
countMap1[t1] ++;
}else{
countMap1[t1] = 1;
}
if (countMap2[t2]) {
countMap2[t2] ++;
}else{
countMap2[t2] = 1;
}
} function typeOf(ele){
var r;
if (ele === null) r = 'null';
else if(ele instanceof Array) r = 'array';
else if(ele === window) r = 'window';
else if(ele instanceof Date) r = 'date';
else r = typeof ele;
return r; } for (i = 0; i < TYPES.length; i++) {
if (countMap1[TYPES[i]] != countMap2[TYPES[i]]) return false;
} return true;
} document.write(arraysSimilar([1,true], [false, 2]));
</script>
</body>
</html>