JavaScript解决一个带验证的Form两个Submit事件（一个页面保持不动【AJAX实现】，一个页面提交并跳转）的场景

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<form class="form-horizontal" action="/biz/patent/edit" method="post" enctype="multipart/form-data" data-toggle="validator" role="form" novalidate="true" id="patentEditForm">
<button class="btn btn-primary" type="button" id="but_sub">保存</button>
<button class="btn btn-primary" type="button">保存返回列表</button>
<button class="btn btn-warning" type="button" onclick="window.location='/biz/project/list';">返回</button>
</form>

$(document).ready(function(){
var buttonId; $('#patentEditForm').validator().on('submit', function (e) {
if (e.isDefaultPrevented()) {
// handle the invalid form...
} else {
// everything looks good!
if(buttonId == "but_sub"){
var formData = new FormData($("#patentEditForm")[0]);
$.ajax({
type:"POST",
url:"/biz/",
data: formData,
dataType:"JSON",
nsync:false,
cache: false,
contentType: false,
processData: false,
success:function(date){
switch(date.status){
case 1:
$success("保存成功！");
break;
case 1009:
$error("保存失败！");
break;
default :
$error("没有提交信息");
}
},
error:function(){
$error("没有提交信息");
}
}); return false;
}
}
}); $(".btn-primary").click(function(){
buttonId = $(this).attr("id");
$('#patentEditForm').trigger('submit');
});