
正文
js数组排序 多条件
提示:扫一扫查出行【扫一扫了解最新限行尾号】
复制提示
按照【次数】和【时间】排序,选择次数最多的排在前面,同样次数的情况下时间较新排在前面。
原始数据 :
var arr= [
{name:'qqq', num:2,time:'2015-06-08 13:44:18'},
{name:'www', num:3,time:'2015-06-08 13:44:18'},
{name:'eee', num:4,time:'2015-06-07 13:40:18'},
{name:'rrr', num:4,time:'2015-06-08 13:44:18'},
{name:'yyy', num:6,time:'2015-06-07 13:40:18'},
];
排序后的数据:
arr= [
{name:'yyy', num:6,time:'2015-06-07 13:40:18'},
{name:'rrr', num:4,time:'2015-06-08 13:44:18'},
{name:'eee', num:4,time:'2015-06-07 13:40:18'},
{name:'www', num:3,time:'2015-06-08 13:44:18'},
{name:'qqq', num:2,time:'2015-06-08 13:44:18'}
];
代码实现:
arr.sort(function(a, b){
if (a.num === b.num) {
return new Date(b.time.replace(/-/g, "/")) - new Date(a.time.replace(/-/g, "/"))
} else {
return b.num - a.num;
}
});






