Django restframwork实现自定义数据格式的分页与搜索

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最近因为在做分页时遇到的问题很多，页浪费了好多时间，所以记录一下。以后如遇到可用省去不必要的麻烦

restframwork中的官方文档对分页和搜索页进行了详细的介绍，但是我公司需要的return的json数据格式进行分层。所以吧，一个很简单的东西，搞的头皮发嘛，看源码之类的，费时，重点是看不太懂，但最后还是参考源码，重写了response方法。

直接上代码了

url(r'^show_workPublished',views.Show_workPublishedView.as_view(),name='show_workPublished'),

serializer.py

class Show_workPublishedModelSerialiazer(serializers.ModelSerializer): class Meta:
model = Upload_filep
#fields = ("id","name","title","img")
fields = ["id","name","title","img",'address','add_time']

自定义分页pagination.py

from rest_framework.pagination import PageNumberPaginationclass PNPageination(PageNumberPagination):
page_size = 6 # 每页显示2条
page_query_param = 'currentPage' # 当前页
page_size_query_param = 'page_size' # 每页显示

view.py

class Show_workPublishedView(generics.ListAPIView):
queryset = Upload_filep.objects.all().order_by('id').reverse()
pagination_class = PNPageination
serializer_class = Show_workPublishedModelSerialiazer #模糊搜索
def get_queryset(self):
name = self.request.GET.get('keyword')
if name is not None:
return self.queryset.filter(Q(name__icontains=name) | Q(title__icontains=name))
return self.queryset def get(self,request,*args,**kwargs):
list = self.get_queryset()
#list = Upload_filep.objects.all()
list_nums = list.count()
try:
page = request.GET.get('currentPage',1)
except PageNotAnInteger:
page = 1
limit = int(request.GET.get('limit',6)) p = Paginator(list,limit)
lists = p.page(page) #lists_serializer = Show_workPublishedModelSerialiazer(lists,many=True)
lists_serializer = self.get_serializer(lists,many=True) ret = {
"result": True,
"msg": "successful",
"secure": False,
"returnCode": "", "data": {
"list":{
"listData":lists_serializer.data, "page_size":limit, #每页显示两个
"totalCount":list_nums , # 一共有多少数据
"totalPage": (list_nums//limit if list_nums%limit==0 else list_nums//limit+1) , # 一共有多少页 a-b if a>b else a+b
"currentPage": page , # 当前页数
},
},
}
return Response(ret)